plotting complex exponential function

Hi friends,
I am tring to plot the graph of
y = (1*e^-i20*pi * t) + (4*e^i20*pi *t ) where t= 5:-0.1:0
can you please help me in this case.
thank you.

 采纳的回答

t = 5:-0.1:0 ;
y = 1*exp(-i*20*pi * t) + (4*exp(i*20*pi *t ) );
plot(t,real(y))

5 个评论

how will the output look?
can u share it here
i am getting a constant y if i use the code u made bro.
t = 5:-0.01:0 ;
for i = 1:length(t)
y(i) = 1*exp(-i*0.2*pi * t(i)) + (0.44*exp(i*0.2*pi *t(i) ) );
end
plot(t,real(y))
t = 5:-0.01:0 ;
%for i = 1:length(t)
y = 1*exp(-i*0.2*pi.*t) + (0.44*exp(i*0.2*pi.*t ) );
plot(t,real(y),'linewidth',2)
Here's what i get
Thank you so much brother, i do really appreciate.

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更多回答(1 个)

E.g., maybe this is what you need
y = 1*exp( -i20 *pi * t ) + 4*exp( i20 * pi * t );
plot(t,y);
Although it is not clear what i20 is. A variable name? Or is this supposed to be i*20? In which case you might want to plot real(y) instead of y.

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提问:

2020-11-29

评论:

2020-11-29

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