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So i have e.g data < 3x3 int 16 >
4 5 3
5 4 1
2 1 2
i wanted to got
78 60 23
and the process is like :
Column 1->(4*4*1)+(5*5*2)+(2*2*3) then Column 2->(5*5*1)+(4*4*2)+(1*1*3) then Column 3->(3*3*1+1*1*2+2*2*3)
i tried this :
[g,h]=size(data);
m = int16(1:g);
t=sum(data(:,m).*data(:,m).*m);
but i have matrix dimension problem, How can i solve,achieve this?
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采纳的回答
Andrei Bobrov
2013-3-12
out = cast((1:size(A,1))*double(A.*A),class(A));
4 个评论
Cedric
2013-3-13
编辑:Cedric
2013-3-13
Andrei type-casts A.*A to double so it can be multiplied by the vector (1:size(..)) avoiding the error that you got when you tried my solution (that I wrote without paying enough attention to the fact that A was int16). He then type-casts back to the original type afterwards (which is the type/class of A).
In my comment above, I type-cast A to double before squaring it, so the square is not truncated by int16 limits. I don't type-cast back to the type of A, because I don't think that you need that (and there would be the truncation issue as the matrix multiplication performs a weighted sum of squares with weights >=1).
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