I'd like to force my exponential fit to start at [0 0]

1 次查看(过去 30 天)
So, I've got some noisy data. When averaged, the data fit nicely along a double exponential fit, starting off with with a positive slope that decays to near 0 (horizontal line).
However, when I want to fit the same curve to the individual traces, things aren't so neat. Sometimes, the slope is initially negative and shallows out, other times, it's flat and then increases exponentially at the end.
How can I force the exponential fit that I want? It seems like 'Startpoint' is a good starting point (heh).
Here's my code:
[u,gof] = fit(time,y,'exp2');
And this doesn't seem to work:
[u,gof] = fit(time,y,'exp2','Startpoint',[0 0]);
??? Index exceeds matrix dimensions.
Any thoughts would be appreciated.
Thanks, Stefan

回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Interpolation 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by