adding varied length vectors to a new matrix sequentially
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I have a for loop which outputs a vector of varying length each time. I want to store each vector as a new row in a new matrix/array/structure (anything). I tried adding a line like this: temp1(:, i) = vec; with my vec to be stored going into a temp matrix. However, this does not work. Any tips on how I can achieve this?
采纳的回答
Matt Tearle
2013-3-20
Sounds like a job for a cell array:
x = cell(n,1);
for k = 1:n
vec = ...;
x{k} = vec;
end
更多回答（1 个）
Azzi Abdelmalek
2013-3-20
for k=1:10
vec=randi(10,1,randi(10),1) % your vector
out{k}=vec
end
2 个评论
mwa710
2013-3-21
Matt Tearle
2013-3-21
In general, you can access data in a cell array the same way: y = x{k} (then plot(y) or whatever). What exactly do you mean by a "raster plot"? This term seems to be context/application dependent. Can you describe the graph you're trying to make? I'm going to guess that you'll need to overlay plots using hold, if you're plotting a bunch of different-sized vectors. If so, you could do this inside the same for-loop that you're using to create/calculate the data in the first place.
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