Please how to calculate the number of 1 and 0 in each position in a binary vector
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For example my vector is like this: Vector = 00000001111000000000111111100000000000000011111111
I want to calculate the number of 0 in each position and the number of 1 in each position like 7zeros4ones9zeros7ones.....
Please need help
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Ameer Hamza
2020-12-5
编辑:Ameer Hamza
2020-12-5
Try this
str = '00000001111000000000111111100000000000000011111111';
x = diff([0 find(diff(str-'0')) numel(str)])
Result
>> x
x =
7 4 9 7 15 8
更多回答(1 个)
Image Analyst
2020-12-5
I see you've already accepted an answer so I guess this isn't what you wanted, but it's what I thought you wanted:
vec = [0,0,0,0,0,0,0,1,1,1,1,0,0,0,0,0,0,0,0,0,1,1,1,1,1,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,1,1,1,1,1,1,1];
% Find the lengths of the stretches of 1's.
props = regionprops(logical(vec), 'Area');
numOnes = [props.Area]
% Find the lengths of the stretches of 0's.
props = regionprops(logical(vec==0), 'Area');
numZeroes = [props.Area]
You'll see the lengths of the runs of both 1's and 0's:
numOnes =
4 7 8
numZeroes =
7 9 15
and it gives the number of 1's and 0's to you explicitly without having to know whether the first element is a 0 or 1 if they're interlaced like Ameer's answer.
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