can someone explain to me what is this entire code means?

2013 3 22
2 个回答
回答已采纳
3 次查看（30 天）

0 个投票

ptotdB = dbp(ptot);
in another file:
function y=dbp(x)
y = -Inf*ones(size(x));
nonzero = x~=0;
y(nonzero) = 10*log10(abs(x(nonzero)));

请先登录，再回答此问题。

 采纳的回答

the cyclist
the cyclist 2013-3-22
编辑：the cyclist 2013-3-22

0 个投票

Looks like it's converting any non-zero input to decibels ( http://en.wikipedia.org/wiki/Decibel ), and zero input to negative infinity.

4 个评论
显示 2更早的评论 隐藏 2更早的评论

lotus
lotus 2013-3-22
seems like the "x" is the input for this case.am i right?
lotus
lotus 2013-3-24
do i have to declare the input value for 'x'?
Walter Roberson
Walter Roberson 2013-3-24
It depends what you mean by "declare". In order to use the function, you need to pass in an input value to the function, but the variable name you use in the calling function does not need to be named "x".

请先登录，再进行评论。

更多回答（1 个）

Ahmed A. Selman
Ahmed A. Selman 2013-3-24

0 个投票

This code finds log10 of the values of some vector (x). The line:
y = -Inf*ones(size(x));
is meaningless in this part of the code because it is overridden later by:
y(nonzero) = 10*log10(abs(x(nonzero)));
There could be more lines in this function that need the variable (nonzero). A much simpler code is:
function y=dbp(x)
y = 10*log10(abs(x(:)))';

2 个评论
显示 无 隐藏 无

lotus
lotus 2013-3-24
i tried it out.but still didn't get the desired answer.no changes at the answer.below is another subfile.i don't know which part that must be fixed to get the value of sfdr=70.9 and snr=60.7:
-mainfile- %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% % Example 4.11 % %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% % % % Pipeline Converter % % % %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% clear all;
%-------------------------------------------------------------------------%
% DAC Static parameters %
%-------------------------------------------------------------------------%
%-------------------------------- Stage 1 --------------------------------%
V_DAC_L1=-0.5;
V_DAC_H1=0.5;
GAIN1=2.0;
VthL1=-0.25+eps;
VthH1=0.25+eps;
%-------------------------------- Stage 2 --------------------------------%
V_DAC_L2=-0.5;
V_DAC_H2=0.5;
GAIN2=2.0;
VthL2=-0.25+eps;
VthH2=0.25+eps;
%------------------------------- Stages 3-9 ------------------------------%
V_DAC_L3=-0.5;
V_DAC_H3=0.5;
GAIN3=2.0;
VthL3=-0.25+eps;
VthH3=0.25+eps;
Vth10=0;
%-------------------------------------------------------------------------%
% Dynamic parameters %
%-------------------------------------------------------------------------%
%-------------------------------- S&H Block-------------------------------%
srH=250e6;
f_TH=600e6;
betaH=1;
tauH=1/(2*pi*betaH*f_TH);
gainH=1;
%-------------------------------- Stage 1 --------------------------------%
sr1=10000e8;
f_T1=6000e6;
beta1=1/2;
tau1=1/(2*pi*beta1*f_T1);
gain1=1;
%-------------------------------- Stage 2 --------------------------------%
sr2=20000e8;
f_T2=6000e6;
beta2=1/2;
tau2=1/(2*pi*beta2*f_T2);
gain2=1;
%------------------------------- Stages 3-9 ------------------------------%
sr=25000e8;
f_T=6000e6;
beta=1/2;
tau=1/(2*pi*beta*f_T);
gain=1;
%-------------------------------------------------------------------------%
% Simulation parameters %
%-------------------------------------------------------------------------%
Ts=1e-8;
Tmax=Ts/2;
Vfs=2;
N=2^12;
Ntransient=20;
Tstop=Ts*(N+Ntransient);
nper=73;
Fs=1/Ts;
Fin=nper*Fs/N; % Input signal frequency (Fin = nper*Fs/N)
f=Fin/Fs; % Normalized signal frequency
bw=Fs/2;
Amp_dB=-0; % Amplitude in dB
Ampl=10^(Amp_dB/20)*Vfs/2; % Input signal amplitude
finrad=Fin*2*pi;
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% Launch Simulation %
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
options=simset('InitialStep', 1, 'RelTol', 1e-3, 'MaxStep', 1,...
'Fixedstep', 1);
sim('Ex4_11',Tstop, options); %Starts Simulink simulation
%-------------------------------------------------------------------------%
% Graphic Outputs %
%-------------------------------------------------------------------------%
w=hann(N);
f=Fin/Fs; % Normalized signal frequency
fB=N*(bw/Fs); % Base-band frequency bins
yfft=y(1+Ntransient:N+Ntransient);
[snr,ptot]=calcSNR(yfft',f,fB,w',N);
ptot=ptot-max(ptot); % Normalize total spectrum
figure(1);
clf;
plot(linspace(0,5E-9*Fs,N/2), ptot(1:N/2), 'r');
grid on;
title('PSD of the Output')
xlabel('Frequency [Hz]')
ylabel('PSD [dB]')
axis([0 5E-9*Fs -140 0]);
sfdr=max(ptot(nper+4:N/2))
snr
-subfile calcSNR-
function [snrdB,ptotdB,psigdB,pnoisedB] = calcSNR(vout,f,fB,w,N,Vref)
% SNR calculation in the time domain (P. Malcovati, S. Brigati)
% vout: Sigma-Delta bit-stream taken at the modulator output
% f: Normalized signal frequency (fs -> 1)
% fB: Base-band frequency bins
% w: windowing vector
% N: samples number
% Vref: feedback reference voltage
%
% snrdB: SNR in dB
% ptotdB: Bit-stream power spectral density (vector)
% psigdB: Extracted signal power spectral density (vector)
% pnoisedB: Noise power spectral density (vector)
%
Vref=1|-1
fB=ceil(fB);
signal=(N/sum(w))*sinusx(vout(1:N).*w,f,N); % Extracts sinusoidal signal
noise=vout(1:N)-signal; % Extracts noise components
stot=((abs(fft((vout(1:N).*w)'))).^2); % Bit-stream PSD
ssignal=(abs(fft((signal(1:N).*w)'))).^2; % Signal PSD
snoise=(abs(fft((noise(1:N).*w)'))).^2; % Noise PSD
pwsignal=sum(ssignal(1:fB)); % Signal power
pwnoise=sum(snoise(1:fB)); % Noise power
snr=pwsignal/pwnoise;
snrdB=dbp(snr);
norm=sum(stot)/Vref^2; % PSD normalization
if nargout > 1
ptot=stot/norm;
ptotdB=dbp(ptot);
end
if nargout > 2
psig=ssignal/norm;
psigdB=dbp(psig);
end
if nargout > 3
pnoise=snoise/norm;
pnoisedB=dbp(pnoise);
end
-subfile dbp-
function y=dbp(x)
% dbp(x) = 10*log10(x): the dB equivalent of the power x
%y = -Inf*ones(size(x));
%nonzero = x~=0;
%y(nonzero) = 10*log10(abs(x(nonzero)));
y = 10*log10(abs(x(:)))';
it is very pleasure if someone can help me with this kind of problems.thanking you in advance.
lotus
lotus 2013-3-24
i got negative value for sfdr and snr=61.4315 which are not the desired answer.

请先登录，再进行评论。

类别

在 帮助中心 和 File Exchange 中查找有关 Spectral Measurements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by