newton's method plotting

7 次查看（过去 30 天）
N/A
N/A 2020-12-8
编辑： Walter Roberson 2020-12-11
here is my code typed out. the hw prompt is below with pictures of my code in mat lab. i keep receiving an error message. once i get the plot to work, i will be able to input my guesses.
inside funq2.m
function (y)=funq2(x);
y=sin(x)-xcos(x);
end
inside citizenone.m
x=-3:0.01:3;
(y)=funq2(x);
plot(x,y)
grid on
  5 个评论
显示 3更早的评论
Walter Roberson
Walter Roberson 2020-12-11
Justin comments:
I keep receiving emails to accept the answer for this question. The person did not answer it, I found the answer on my own. Please stop emailing me to accept an answer that was not an answer. Thank you.
Walter Roberson
Walter Roberson 2020-12-11
Justin:
You could post the solution you found as an Answer and then Accept your Answer.

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

David Hill
David Hill 2020-12-8
Something like this:
f=@(x)sin(x)-x.*cos(x);
fp=@(x)cos(x)+x.*sin(x)-cos(x);
x=-3:.01:3;
plot(x,f(x));
%% Newton's Method
X(1)=initialGuess;%provide an initial guess
error=1;
tol=1e-6;%provide a tolerance
count=1;
while error>tol
X(count+1)=X(count)-f(X(count))/fp(X(count));
error=abs(X(count+1)-X(count));%or however you want to determine the error
count=count+1;
end
  3 个评论
显示 1更早的评论
David Hill
David Hill 2020-12-8
You are suppose to use Newton's method to solve. Have you studied Newton's method? I suggest you look at it: https://en.wikipedia.org/wiki/Newton%27s_method
I did not provide a complete solution. You need to plug in your initial guess for the root. The final answer will be in the end of the X array.
N/A
N/A 2020-12-8
Yes, I had it reviewed in my class, yet my teacher does not make sense. I will find a tutor. Thank you for your time.

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 MATLAB 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by