Integral operator in a for loop

17 次查看(过去 30 天)
Hi folks! I am trying to calculate the integral of a function while it is in a loop,but MATLAB gives error. How can I change "v" each time? this is the code
f=@(y) sqrt(y)/(1+exp(y/v))
for v=-5:0.1:5
q(i)=integral(f,0,inf);
end
  6 个评论
José Anchieta de Jesus Filho
编辑:José Anchieta de Jesus Filho 2020-3-6
I thought that this way it would be easier to understand. I'm sorry for this
dF = @(z1,r) 2.*pi.*v.*ro.*(Brt(z1,r).^2).*r; % v, ro they are scalar numbers
p1 = @(r) integral(@(z1) dF(z1,r),z0,z0+e,'ArrayValued',true);% e is also a scalar
F = integral(@(r) p1,ri,re,'ArrayValued',true);
c = F./v
that's my role in response to z0. what I need is for it to be calculated with the z0 varying
z0 = 0:0.001:0.03
for each variation of z0, I will have a new p1, a new F and, consequently, a new c. I want to plot a graph of z0 versus c

请先登录,再进行评论。

回答(2 个)

Andrei Bobrov
Andrei Bobrov 2013-3-27
编辑:Andrei Bobrov 2013-3-27
v = -5:.1:5;
f = @(y)sqrt(y)./(1+exp(y./v));
q = integral(f,0,inf,'ArrayValued',true);

Matt J
Matt J 2013-3-27
vdata=-5:0.1:5;
n=length(vdata);
q=zeros(1,n);
for i=1:n
v=vdata(i);
f=@(y) sqrt(y)/(1+exp(y/v));
q(i)=integral(f,0,inf);
end

类别

Help CenterFile Exchange 中查找有关 Matrix Indexing 的更多信息

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by