Trying to make a piecewise function that isn't for graphing or using the piecewise function itself

Question

Kylenino Espinas 2020-12-9

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/688644-trying-to-make-a-piecewise-function-that-isn-t-for-graphing-or-using-the-piecewise-function-itself

编辑： James Tursa 2020-12-9

function y = project2Tester(x)
  y = zeros(size(x));
    
  x1 == (x <= -1);
  y(x1) = log(abs(x));
  x2 == (-1 < x & x < 0);
  y(x2) = abs(x);
  x3 == (0 <= x & x < 1);
  y(x3) = x;
  x4 == (x >= 1);
  y(x4) = log(x);
  y(~(x1 | x2 | x3 | x4)) = 0;
end

Is my code. If I use = instead of == an error occrurs as well. If I use x1/2/3/4 instead of x into the y(x) = it still doesn't work. I'm kinda confused on where to go because I've tried everything.

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Answer 1

James Tursa 2020-12-9

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/688644-trying-to-make-a-piecewise-function-that-isn-t-for-graphing-or-using-the-piecewise-function-itself#answer_570479

编辑：James Tursa 2020-12-9

在 MATLAB Online 中打开

Use logical indexing on both sides of the assignment. E.g.,

function y = project2Tester(x)
  y = zeros(size(x));
    
  x1 = (x <= -1);
  y(x1) = log(abs(x(x1)));
  x2 = (-1 < x & x < 0);
  y(x2) = abs(x(x2));
  x3 = (0 <= x & x < 1);
  y(x3) = x(x3);
  x4 = (x >= 1);
  y(x4) = log(x(x4));
  y(~(x1 | x2 | x3 | x4)) = 0;  % not really needed since you initialized y to 0's
end