error with sqrt in Matlab
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hi, help please when I put this formula GEH2= sqrt(2*int64((flujo_sim2-FlujoReal2)^2)/int64(flujo_sim2+FlujoReal2)) in matlab, this returns me the following error: Check for missing argument or incorrect argument data type in call to function 'sqrt'.
why does this error give me?
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Steven Lord
2020-12-11
The sqrt function is not defined for variables of the int64 data type. The square root of an integer value is not necessarily itself an integer value. If it were defined, what exactly would you expect x to be in the following code?
five = int64(5)
x = sqrt(five)
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Steven Lord
2020-12-14
The lines of code you posted doesn't tell me the class of the variables, which is the important information.
But I repeat my previous question. If you have an int64 number that is not a perfect square, would you be okay with getting an answer that when squared does not give you back the original number?
sqrtDouble = sqrt(5)
sqrtInt = int64(sqrt(5))
sqrtDouble.^2 - 5 % close to 0
sqrtInt.^2 - 5 % not really close to 0
Théophane Dimier
2020-12-11
Hi, sqrt does not accept int64 as input. If you want to round the quantity first, use round, ceil or floor functions instead
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David Hill
2020-12-11
Cannot take sqrt of int64 data type. Take sqrt of double then round and convert to int64.
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