how to solve the error? Error in fixed_point_3 (line 10) while iter <= max_iter
2 次查看(过去 30 天)
显示 更早的评论
function [x] = fixed_point_3(init,error,max_iter)
% 2x^3 + 4x^2 - 10 = 0 can be written as
% 4x^2 = 10 - 2x^3 --> x^2 = 1/4 *(10 - 2x^3)
% if only positive root is taken, then x = 1/4 ((10 - 2x^3)^(1/2)
%now we can use fixed point iteration
iter = 0;
now
%max_iter = maxium number of iterations
while iter <= max_iter
max_iter = 7.3814e+05;
x = (1/4)*((10- init^3)^(1/2));
iter = iter + 1;
if abs(x-init)<error
return
end
end
2 个评论
Matt Gaidica
2020-12-13
I don't get an error passing in (1,1,1). Note: it's bad practice to use init and error as variable names, those are reserved in MATLAB. Also, use a code block to share.
function [x] = fixed_point_3(init,error,max_iter)
% 2x^3 + 4x^2 - 10 = 0 can be written as
% 4x^2 = 10 - 2x^3 --> x^2 = 1/4 *(10 - 2x^3)
% if only positive root is taken, then x = 1/4 ((10 - 2x^3)^(1/2)
%now we can use fixed point iteration
iter = 0;
now
%max_iter = maxium number of iterations
while iter <= max_iter
max_iter = 7.3814e+05;
x = (1/4)*((10- init^3)^(1/2));
iter = iter + 1;
if abs(x-init)<error
return
end
end
Walter Roberson
2020-12-13
??
init is used in some obscure methods such as idnlarx but it is by no means reserved.
error() is not actually reserved, but it is not a great idea to use it as a variable name.
回答(0 个)
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!