adding a struct to struct array
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I like to return mutltiple outputs from a function as a struct. Many times I call the function in a loop and I want to gather the results for all iterations as a struct array. Then I can, for example, access all individual fields using a bracket.
My question is how to add the return-structs to the struct array so each member of the array has the return-struct fields.
This does not work:
>> sarry = struct([]);
>> sarry(end+1) = myfunc(foo);
??? Subscripted assignment between dissimilar structures.
I wrote a function that does what I want--see below.
Is there an easier way to do it?
Bob
p.s. here is my function:
function sarray = AddStruct2StructArray(sarray,s)
fnames = fieldnames(s);
sarray(end+1).(fnames{1}) = s.(fnames{1});
if length(fnames) > 1
for k = 2:length(fnames)
sarray(end).(fnames{k}) = s.(fnames{k});
end
end
p.p.s. I ran across this idea but it assumes that the inputs to the function in different iterations of the loop are the integers. It could be extended but does not allow other code within the loop.
T = arrayfun(@(K) CreateAsStruct(K), 1:n, 'UniformOutput',0);
array = horzcat(T{:});
clear T
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Darik
2013-4-1
编辑:Darik
2013-4-1
You can skip the first assignment of the empty struct, a la
clear sarray; sarray(1) = myfunc(foo);
So you could just run the for loop backwards to combine the array preallocation and the function calls: clear sarray; for i = n:-1:1 sarray(i) = myfunc(foo(i)); end
Those 'clear sarray' lines aren't necessary, it's just to make clear that sarray hasn't been defined before the first indexed assignment
2 个评论
Darik
2013-4-1
The code formatting isn't working for me for some reason, not sure what's up with that
Darik
2013-4-1
And if you can't run the loop backwards, you can include an extra preallocation step like this:
clear sarray;
sarray(1:n) = myfunc(foo(1));
for i = 2:n
sarray(i) = myfunc(foo(i));
end
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