Output argument not assigned during call

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Joe
Joe 2013-4-3
I get this error message when I try to run a function that I created. I understand what this is saying, but when I look at my function, the output argument is already correctly defined within the function. So what else could be wrong?
Here is the function:
function y = linInt(xData,yData,x)
if x < xData(1) || x > xData(end)
error('values in x out of range')
else
for i = 1:x
y(i) = yData(i) + ((yData(i+1)-yData(i))*(x-xData(i))/(xData(i+1)-xData(i)));
end
end
end

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采纳的回答

Walter Roberson
Walter Roberson 2013-4-3
When the code executes, for some reason the statement that assigns a value to the output variable is not being reached. This can happen due to logic errors in how the code was written.
You could post the code for us to examine, or you could use the debugger to trace the flow of the code.
  1 个评论
Walter Roberson
Walter Roberson 2013-4-3
Your code
for i = 1:x
should be
for i = 1 : length(xData)
Remember, your provided x could be negative.

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Alexandra
Alexandra 2013-4-3
You only assign an output value for y, if the else-branch is executed. You also need to assign a value for y for the if-branch. E.G.
if ...
y = [];
else
y = ...;
end

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