Why I get 1×0 empty double row vector?

4 次查看（过去 30 天）
Aleksandra Pawlak
Aleksandra Pawlak 2020-12-27
评论： Image Analyst 2020-12-28
Hi, I have problem with my code. I don't know why fidx1 is 1x0 empty double row vector?
min(oh1) and max(oh1) results are:
>>min(oh1)
ans = 102.8890
>> max(oh1)
ans = 106.2470
d1=[0 min(oh1) min(oh1)];
e1=[max(oh1) max(oh1) max([oh1 oh2 oh3 oh4 oh5 oh7 oh11 oh13 oh19 oh23 oh25 oh29 oh35 oh37])];
X1=[xq1];
Y1=[100*r1];
lidx1 = find(X1 == max(oh1));
Ylidx1 = Y1(lidx1);
fidx1 = find(X1 == min(oh1));
Yfidx1 = Y1(fidx1);
  4 个评论
显示 2更早的评论
Aleksandra Pawlak
Aleksandra Pawlak 2020-12-27
My code works only for max value.
There's something wrong with part:
fidx1 = find(X1 == min(oh1));
Yfidx1 = Y1(fidx1);
I can't understand this

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Ive J
Ive J 2020-12-27
编辑：Ive J 2020-12-27
xq1 (and therefore X1) simply may don't contain min(oh1) since you are discretizing [0, max(oh1)]. What you can do is to find the idx corresponding to the closest value to min_oh1
max_oh1 = 104;
xq1 = 0:104/200:104;
[~, fidx1] = min(abs(xq1 - min(oh1)));
  5 个评论
显示 3更早的评论
Ive J
Ive J 2020-12-27
The first output argument is the minimum value itself, and the second one is it's index.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by