How to make this loop faster?

1 次查看（过去 30 天）
Oliver Lestrange
Oliver Lestrange 2020-12-27
评论： Jesús Zambrano 2020-12-28
Hello,
The following code takes 30 seconds to execute. I can't make it any faster.
Any suggestion?
Thanks!
function [ at] = obstacleAttenuation( Ant, Movel, Obstaculo,mapa )
tic
fprintf('\nInside obstacleAttenuation function!\n');
at = zeros(mapa.xlength, mapa.ylength);
for xi=1:mapa.xlength
for yi=1:mapa.ylength
att = 0;
[x, y] = bresenham(Ant.Antena_x, Ant.Antena_y, Movel.x(xi), Movel.y(yi));
for i = 1:length(x)
Obs = Obstaculo(x(i), y(i));
att = att + Obs;
end
at(xi, yi) = att;
% Obs = Obstaculo(x(1:length(x)), y(1:length(x)));
% att = sum(sum(Obs));
% at(xi, yi) = att;
end
end
fprintf('\nExit obstacleAttenuation function!\n');
toc
end
NOTE: I am using R2016a version.

请先登录，再回答此问题。

回答（1 个）

Jesús Zambrano
Jesús Zambrano 2020-12-27
Is it possible to enter vectors as arguments in the function Obstaculo and get a vector as result? If so, then you could try replacing:
for i = 1:length(x)
Obs = Obstaculo(x(i), y(i));
att = att + Obs;
end
By:
i=1:length(x);
att = sum(Obstaculo(x(i), y(i)));
  12 个评论
显示 10更早的评论
Oliver Lestrange
Oliver Lestrange 2020-12-28
Obstaculo has numbers like 14.3, 0, 23... Maybe I should just resize the image...
Thanks for your time!

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by