How to make this loop faster?

1 次查看(过去 30 天)
Oliver Lestrange
Oliver Lestrange 2020-12-27
Hello,
The following code takes 30 seconds to execute. I can't make it any faster.
Any suggestion?
Thanks!
function [ at] = obstacleAttenuation( Ant, Movel, Obstaculo,mapa )
tic
fprintf('\nInside obstacleAttenuation function!\n');
at = zeros(mapa.xlength, mapa.ylength);
for xi=1:mapa.xlength
for yi=1:mapa.ylength
att = 0;
[x, y] = bresenham(Ant.Antena_x, Ant.Antena_y, Movel.x(xi), Movel.y(yi));
for i = 1:length(x)
Obs = Obstaculo(x(i), y(i));
att = att + Obs;
end
at(xi, yi) = att;
% Obs = Obstaculo(x(1:length(x)), y(1:length(x)));
% att = sum(sum(Obs));
% at(xi, yi) = att;
end
end
fprintf('\nExit obstacleAttenuation function!\n');
toc
end
NOTE: I am using R2016a version.

回答(1 个)

Jesús Zambrano
Jesús Zambrano 2020-12-27
Is it possible to enter vectors as arguments in the function Obstaculo and get a vector as result? If so, then you could try replacing:
for i = 1:length(x)
Obs = Obstaculo(x(i), y(i));
att = att + Obs;
end
By:
i=1:length(x);
att = sum(Obstaculo(x(i), y(i)));
  12 个评论
Oliver Lestrange
Oliver Lestrange 2020-12-28
Obstaculo has numbers like 14.3, 0, 23... Maybe I should just resize the image...
Thanks for your time!

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by