Unable to perform assignment because the size of the left side is 1-by-10 and the size of the right side

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Bradley Kitzul 2020-12-27

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https://ww2.mathworks.cn/matlabcentral/answers/703462-unable-to-perform-assignment-because-the-size-of-the-left-side-is-1-by-10-and-the-size-of-the-right

评论： Walter Roberson 2020-12-29

采纳的回答： Walter Roberson

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Hi, I am getting this error message.

Unable to perform assignment because the size of the left side is 1-by-10 and the size of the right side

is 1-by-6.

Error in codeRun (line 57)

[z_1,b(1, 1:10),terms_1,candIndex(1, 1:9)]= FOS(inp1,N/3,M,NO,trm1,t);

I am not sure why I am getting this error message as the only thing I am changing is getting rid of white gaussian noise to my signal (commented out and replaced it with just y.

% adding white gaussian noise to the signal
%in1=y;
%v = awgn(y,5,'measured'); 
%in=in1+v;
in = y;

Sorry if my question in rudimentary, I am new to coding! Thank you :D

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Cris LaPierre 2020-12-28

We don't have enough of your code to really say for certain why this change is causing this error. For starters, please include the entire error message (all the red text).

You might consider attaching your code and data files if there are any using the paperclip icon so we can try to reproduce the error on our end.

Bradley Kitzul 2020-12-28

Hi, my files are attached.

The error arises when I replace lines 35-37 with 38 of codeRun... I am getting rid of the white gaussian noise added to the signal. Futhermore, that is the full error message.

Note: When running the code, if it gets stuck on gmax..just run the code again.

Let me know if you have any other questions. Thank you!

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Answer 1

Walter Roberson 2020-12-28

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在 MATLAB Online 中打开

    if (abs(Qmax) < abs(Q1))
        noise=1; % only noise remains
    else
        % complete searching
        mse=mse-Qmax;
        D=Dmax;
        p=pmax;
        c=cmax;
        g=gmax;
        alpha=alphamax;
        m=m+1;
    end

When you detect noise, you do not increase m . There will be a variable number of segments detected as noise, so you expect a variable output for m.

M=m-1;
terms=M; %# of terms chosen by FOS

So M is expected to vary in size.

a(1)=g(M);
for i=1:M
    v(i) = 1;
    for m = i+1:M
        v(m) = - sum(alpha(m, i:m-1) .* v(i:m-1));
    end
    a(i) = sum(g(i:M) .* v(i:M));
end

You create up to a(M), so a will vary in size.

[z_1,b(1, 1:10),terms_1,candIndex(1, 1:9), eratio]= FOS(inp1,N/3,M,NO,trm1,t);

but your code is expecting a vector of exactly 10 values each time.

M=10;% Maximum term to add

Notice the "maximum". Not a fixed number, a maximum.

Your code should be receiving the output into an un-indexed variable, and doing something with results that are shorter because noise was detected. Pad them with zeros or something. And only then write the result into b.

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Bradley Kitzul 2020-12-28

Hello again,

Thank you for the help! However, I am still a little confused on the solution. Sorry for the inconvenience.

Walter Roberson 2020-12-29

在 MATLAB Online 中打开

[z_1,bt,terms_1,candIndex(1, 1:9), eratio]= FOS(inp1,N/3,M,NO,trm1,t);
bt(11)=0;  %pad short
b(1,1:10) = bt(1:10);

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