How do I create a function that takes a character array (s) as an input and returns a new character array with each letter shifted forward once in the alphabet?

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Sean
Sean 2013-4-9
评论： irfan KHAN 2020-12-25
Assume that the input s will never contain the letter 'z'.
Example:
>> shiftletters('apple')
ans =
bqqmf
So far this is what I have and it must be because I'm an idiot but I can't get any further. Thank you in advance.
* function s = shiftletters('apple')
s=char('[A-Z]'+1);*
I believe my problem lies in the fact that I do not know how to correctly identify the letters of the alphabet into a single variable or array.
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Yao Li
Yao Li 2013-4-9
Do you mean if the string is 12345abcdz23, the result should be 12345bcdea23? Currently, you function runs well except 'z' and the characters beyond alphabet. So before the shift, try to find out whether there are 'z' in the string and which charaters needs to be shifted.
irfan KHAN
irfan KHAN 2020-12-25
can anyone help me in the following
Create a variable named str which contains the characters 'wxyz'. Shift it forwards by three characters (i.e., add 3 to the ascii code). What is the result?

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采纳的回答

Friedrich
Friedrich 2013-4-9
编辑：Friedrich 2013-4-9
Hi,
you maybe need to think about the letter z/Z, but in general you can do:
function s = shiftletters(in)
s = char(in+1);
In the case z/Z should stay:
function s = shiftletters(in)
non_z = ~( (in=='z') | (in=='Z'));
s = in;
s(non_z) = char(in(non_z)+1);

更多回答（1 个）

Yao Li
Yao Li 2013-4-9
编辑：Yao Li 2013-4-9
function s=shiftletters(input_string)
for i=1:1:length(input_string)
if((double(input_string(i))>=65&&double(input_string(i))<=89)...
||(double(input_string(i))>=97&&double(input_string(i))<=121))
input_string(i)=char(input_string(i)+1);
elseif((double(input_string(i))==90)||(double(input_string(i))==122))
input_string(i)=char(input_string(i)-25);
end
end
s=input_string;

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