erfc with complex number

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rahman
rahman 2011-5-10
评论： Dilip Jose 2020-2-13
Hi all
I want to compute erfc(.) of a complex number. How can I do that? Is there any way to use erfc(.) of matlab?

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Matt Fig
Matt Fig 2011-5-10
A quick search of the FEX turned up these two. There may be others...
File 1
File 2
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Walter Roberson
Walter Roberson 2020-2-5
To check, you have
d2=(8*m^3/2);
Is it possible that that should be
d2=(8*m^(3/2));
The current expression would be equivalent to the clearer
d2=4*m^3;
Or even 8/2 instead of 4 if that somehow made documentation sense. With the /2 where it is and with the leading multiplier already even, people are going to wonder.
Dilip Jose
Dilip Jose 2020-2-13
thank you so much sir ...got some results...hope the best.

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