using mle in matlab

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shalini sharma
shalini sharma 2021-1-13
回答： w w 2021-6-23
for a given dataset i need to calculate parameters value using mle where cdf = a*(1-exp(-b*A)) and pdf = a*b*exp(-b*A),if i use following code
A=[6 10 17 20 29 34 38 41 50 55 ];
[phat,pci] = mle(A,'pdf',@(A,x,y) x*y*exp(-y*A),'start',[1,1])
i get
Error using mlecustom>llf_pdfcdf
(line 440)
The PDF function returned negative
or zero values.
Error in fminsearch (line 330)
x(:) = xe; fxe =
funfcn(x,varargin{:});
Error in mlecustom (line 184)
fminsearch(llf,start,opts,uncensData,censData,uncensFreq,censFreq,fun1Args,fun2Args,checkFunVals,lb,ub);
Error in mle (line 247)
[phat, pci] =
mlecustom(data,varargin{:});
I am not able to understand what is wrong and how to rectify it as i am new to matlab.Please help how sholud i evaluate parameters a and b using mle function in matlab.

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采纳的回答

w w
w w 2021-6-23
try 'lowerbound'

更多回答（1 个）

Jeff Miller
Jeff Miller 2021-1-13
One problem is that mle's search function (fminsearch) may try negative parameter values, in which case your pdf function returns a negative value. You could avoid that problem by squaring the parameter values, like this:
[phat,pci] = mle(A,'pdf',@(A,x,y) x^2*y^2*exp(-y^2*A),'start',[1,1])
If you do that, just keep in mind that the "real" x and y values you want are the squares of the phat values returned by mle.
Another problem, though, is that these are not legitimate pdf and cdf functions except when a=1. So, I think you really only have one parameter to estimate here--namely, your y parameter. It looks to me, anyway, like you are fitting an exponential distribution to these A values and looking for the best-fitting rate parameter. That value is 0.03333 = 1/mean(A)
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Elifnur Öztürk
Elifnur Öztürk 2021-5-22
Did you find the answer to your question? @shalini sharma
shalini sharma
shalini sharma 2021-5-26
I tried using the square of parameters in equation to be evaluated...and also with used different PDF and cdf but every time I got error....anyway thanks ....will try again

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