Could someone explain this straight line function?

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Jack Rimmer
Jack Rimmer 2021-1-14
回答： David Hill 2021-1-14
I found this bit of code in another help thread:
func = @(x)a(1) + (a(2)-b(2))/(a(1)-b(1))*(x-a(1));
I have gotten it to work in matlab fine but I dont actually understand what it is doing on a mathimatical level.
Could someone explain so I solve some errors im having with similar functions?
Thanks

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采纳的回答

Stephan Ciobanu
Stephan Ciobanu 2021-1-14
Hi!
a(1) % extracts the first element of array a
a(2) % extracts the second element of array a
if a is an array: with
and b, similarly, with
func is:

更多回答（1 个）

David Hill
David Hill 2021-1-14
It is point-slope form of a line. If the points are a=[x2, y2] and b=[x1, y1], then:
m=(a(2)-b(2))/(a(1)-b(1));%slope
func =@(x) m*(x-a(1))+a(2);%above equation seems to be wrong, should be +a(2)
func =@(x) m*(x-b(1))+b(2);%same thing just using other point

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