Reynolds number, FalsePosition getting multiple errors with no output

1 次查看(过去 30 天)
I am to create a function that uses FalsePosition (function shown below) to solve for f in the given equation. I think I'm missing some connections between my script and the function I'm trying to call.
Here is FalsePosition
This is my code:
function [root, fx, ea, iter] = falsepositionnew(y)
xl = 2500;
xu = 1000000;
es = 0.0000001;
maxit = 200;
Re = 10000:200000;
y = @(f, Re) 1/sqrt(f) - 4*log(Re*sqrt(f))+0.4; %equation given
for = i:numel(Re)
f(i) = falseposition(y,xl,xu,es,maxit);
end

回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Statics and Dynamics 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by