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Why am I getting this error "??? error using ==> times matrix dimensions must agree" in matlab?

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Debajyoti
Debajyoti 2013-4-21
design a FIR low pass filter using Kaiser window
a1phap=0.1
a1phas=44
ws=30
wp=20
wsf=100
B=ws-wp
wc=0.5*(ws+wp)
wcr=wc*2*pi/wsf
D=(a1phas-7.95)/14.36
N=ceil((wsf*D/B)+1)
a1pha=(N-1)/2
gamma=(.5842*(a1phas-21).^(0.4)+0.07886*(a1phas-21))
n=0:1:N-1
hd=sin(wcr*(n-a1pha))./(pi*(n-a1pha))
hd(a1pha+1)=0.5
wk=(kaiser(N,gamma))
hn=hd.*wk % *(HERE I AM GETTING THIS ERROR)*
W=85:5:120
h=freqz(hn,1,W)
plot(W/pi,20*log10(abs(h)))
those two matrices have the same dimensions of 27..still why this error?

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采纳的回答

Cedric
Cedric 2013-4-21
You have to transpose either wk or hd, because one is a column vector and the other a row vector. E.g.
hn = hd .* wk.'

更多回答（2 个）

the cyclist
the cyclist 2013-4-21
编辑：the cyclist 2013-4-21
I don't have the Signal Processing Toolbox, so I can't execute the kaiser() function. However, the documentation indicates that it will output a column vector. Your vector hd is a row vector, so it does not actually have the same dimension. You need to transpose one of them.
Chandra Shekhar
Chandra Shekhar 2013-4-21
编辑：Chandra Shekhar 2013-4-21
Don't use dot product,edit that line like this
hn=hd*wk;
but you will get single value after multiplying,but 'freqz' function requires vector as a input.
if you need vector then do like this, you will get waveform.
hn=hd. * wk ' ;

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