How to add values to already existing ones in a matrix using for loop?

2013 4 21
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Hi, my function looks like this:
nEN=[1 2 4 5];
KG=[];
for i1=1:4
KG((2*(nEN(i1))-1),(2*(nEN(i1))-1))=Ke((2*i1-1),(2*i1-1));
KG(2*(nEN(i1)),2*(nEN(i1)))=Ke((2*i1),(2*i1));
end
Basically it assigns values from matrix 'Ke' (8x8 with constants) to matrix 'KG' which is initially filled with zeros. Numbers of rows and columns are given by the array nEN, which varies in another loop which is not shown here. The thing is sometimes nEN can have the same values as those obtained in the previous iteration, and so my loop rewrites the values which have been already present in 'KG', but I want them to be added together instead. How can I do that?? Thanks.

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Vitaly
Vitaly 2013-4-21

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Nevermind, I solved the problem by accumulating values in KG with:
KG((2*(nEN(i1))-1),(2*(nEN(i2))-1)) = KG((2*(nEN(i1))-1),(2*(nEN(i2))-1)) + Ke(((2*i1)-1),((2*i2)-1));
and so on..

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Cedric
Cedric 2013-4-21
编辑：Cedric 2013-4-21

1 个投票

Like this:
KG = zeros(size(Ke)) ; % Prealloc (are they same size?)
% and initialize with 0's.
for ...
nEN = [1 2 4 5] ; % Defined in the external loop.
for i1 = 1 : 4
bi_KG = 2 * nEN(i1) ; % Base index for KG.
bi_Ke = 2 * i1 ; % Base index for Ke.
KG(bi_KG-1,bi_KG-1) = KG(bi_KG-1,bi_KG-1) + Ke(bi_Ke-1,bi_Ke-1) ;
KG(bi_KG,bi_KG) = KG(bi_KG,bi_KG) + Ke(bi_Ke,bi_Ke);
end
end

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Cedric
Cedric 2013-4-21
You're welcome; note that I edited my answer a minute after posting it because I had made a mistake by copy/paste-ing a little to fast.

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