How to generate C code for the matlab function "kurtogram"?

Question

HF 2021-1-30

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https://ww2.mathworks.cn/matlabcentral/answers/731488-how-to-generate-c-code-for-the-matlab-function-kurtogram

评论： HF 2021-1-31

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Hello,

I am trying to generate C code for my Matlab code. My Matlab code runs perfectly without any problems.

To generate the C code, I am using the Matlab C coder.

However, while trying to generate C code for the Matlab function kurtogram I always get some errors. When I try generate C code for kurtogram without any output parameters, I am able to generate C code.

Does anyone know how to solve this or what I am possibly doing wrong.

This is the function I would like to have in C code:

function [fc, BW] = causprobieren (x,sampRate)
    double fc
    double BW
    [~, ~, ~, fc, ~, BW] = kurtogram(x, sampRate);
end

I am using this script for testing the function:

sampRate = 1000;
X = X';
[fc, B] = causprobieren(X(1:2500),sampRate)

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Answer 1

Walter Roberson 2021-1-30

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double fc

is the same thing as

double('fc')

which means to convert the character codes for 'f' 'c' to double precision and display them. It has nothing to do with declaring fc to be double precision.

You need to assign zeros of appropriate size to fc before you make the call, or you need to use coder.varsize().

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Walter Roberson 2021-1-31

When I read the documentation, it looks like in this case you should not initialize a and b

HF 2021-1-31

在 MATLAB Online 中打开

I already tried this option too, but I am still not able to generate C code:

function [fc, BW] = causprobieren (x,sampRate)
    %#codegen
    coder.varsize('a');
    coder.varsize('b');
    [~, ~, ~, a, ~, b] = kurtogram(x, sampRate);
    % kurtogram(x, sampRate);
    fc = a;
    BW = b;
end