How can i find the solution of the equation when the R.H.S also contains the unknown??

1 次查看（过去 30 天）
Naveen Ramesh
Naveen Ramesh 2013-4-23
I have this eqaution that need to be plotted between s_y and beta. But the problem is that, the R.H.S also contains the quantity beta but under a different math term. This is the eqation:
beta=acosd((((R^2-((R*u*sin(beta))/(R-d))^2)^0.5*(R-d))/(R*u))-(s_y/u));
Except for Beta, all the values are known and s_y has been defined as
s_y=0:0.1:35;
How can i do this?? meaning, how can i solve for beta? am new to matlab and just learning the basics. So if anybody is able to help me with this,I ll be grateful.....
  3 个评论
显示 1更早的评论
Walter Roberson
Walter Roberson 2013-4-23
Are you sure? You are using acosd() implying that beta is in degrees, but you use sin(beta) implying that beta is in radians.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Walter Roberson
Walter Roberson 2013-4-23
Assuming radians,
atan2(sqrt(-(-d+R-s_y+u) .* (-d+R+s_y-u) .* (-d+R+s_y+u) .* (-d+R-s_y-u)) ./ (u.*s_y), (R.^2-2.*R.*d-u.^2+d.^2-s_y.^2) ./ (u.*s_y))
and also the negative of that.
  2 个评论
Naveen Ramesh
Naveen Ramesh 2013-4-24
yu mean there are 4 solutions ??? coz there is a comma in the answer that yu have given and also yu mentioned that the negative of this also forms the answer... ??
Walter Roberson
Walter Roberson 2013-4-24
There are two solutions. atan2() is the arctan function that requires two arguments in order to properly figure out which quadrant to use, so atan2() is going to return one value. The negative of that value is also a solution for a total of two solutions.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Mathematics 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by