how to convert numstrng to integers and take lcm
显示 更早的评论
consider out 2 =
1 0 0 1 0 1
1 1 1 1 0 1
1 1 0 1 1 1
if i need to take the lcm of the binary rows that have in out2 i am doing this:
converting each row to numstrng using: out3 = num2str(out2(:))
now i need to pick 1 to m rows of this string (m = 5 here) and convert it to decimal but it wont work: out 4 = bin2dec(out3(1:1:5))
then i need to take the lcm of out4
x = lcm(out4)
% but the lcm function wont work for more than two numbers which is pretty challenging here, how to work through this
采纳的回答
Andrei Bobrov
2013-4-24
Try this:
out2 = [
1 0 0 1 0 1
1 1 1 1 0 1
1 1 0 1 1 1];
out4 = out2*2.^(size(out2,2)-1:-1:0)';
out_pair = nchoosek(out4,2);
out5 = num2cell(out_pair,1);
out_last = [out_pair, lcm(out5{:})];
5 个评论
Malik
2013-4-24
Malik
2013-4-24
Malik
2013-4-26
Malik
2013-4-26
Andrei Bobrov
2013-4-26
out = dec2bin(out_last(:,end)) - '0';
更多回答（1 个）
Vineet
2013-4-24
0 个投票
You can put all the numbers in an array and take LCM of 2 numbers at a time.
Say, you begin with the LCM of the first and the second number. Whatever LCM you get now, treat it as a new number and calculate LCM of this number and the next number in the list.
Run a loop for the same.
类别
在 帮助中心 和 File Exchange 中查找有关 Discrete Math 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
