How to decompose a 4th order tensor

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Derek Cooper
Derek Cooper 2021-2-3
编辑： Derek Cooper 2021-2-4
Hello
Is there any matlab function to decompose a 4th order tensor?

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回答（2 个）

Christine Tobler
Christine Tobler 2021-2-3
The value of K1111 is overwritten with the next value in every loop iteration - is this your intention, or did you maybe mean to add them up? That is, for example,
K1111 = K1111 + inv(J) * F(a,A) * F(b,B) * K(A,B,K,D) * F(K,K) * F(d,D);
I'm also getting the impression you're using the same variable name K for both the iterator in the for-loop and the tensor K you're operating on. The formula you wrote up was using F(c, C) instead of F(K, K) in the code.
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Derek Cooper
Derek Cooper 2021-2-3
Thanks for you answer.
The sought is components of matrix M and yes i want to add them upp. and K(A,B,C,D) is taken with respect of positions of K in an old M matrix. I hope you answerstand. The positions are the same as in M.
Christine Tobler
Christine Tobler 2021-2-3
But your code is using K(A, B, K, D), not K(A, B, C, D). Can you confirm if this is correct? I don't think the code matches up with the definition you've written above, but I'm not sure which of the two fits what you want to compute.

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Derek Cooper
Derek Cooper 2021-2-3
编辑：Derek Cooper 2021-2-3
Sorry you are right, it should be K(A,B,C,D), and is components of D. so maybe its appropriate to write it as D(A,B,C,D).
  2 个评论
Christine Tobler
Christine Tobler 2021-2-3
Is D a scalar index from 1 to 3, or is it a 4-dimensional array? It seems to be used for both, maybe there should be a different variable name for one of them, too.
Derek Cooper
Derek Cooper 2021-2-3
D is a 3x3 matrix, not a 4 dimentional array. The reason why ABCD is used is because if K1111 is sought, then the value of D(1,1) should be taken since K1111 belongs to the same position as D(1,1)

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