Simple MATLAB (noob) question

3 次查看(过去 30 天)
Hello,
I not a frequent user to this program and I'm running into a little problem regarding graphing a function.
First I input this: x = 0:pi/15:4*pi
so that I can develop a range of the x values next I enter: y = (2*cos(60*x))
but it all comes out equaling two, when it shouldn't. I don't know where I'm going wrong. Help would be appreciated.

采纳的回答

Wayne King
Wayne King 2013-4-26
编辑:Wayne King 2013-4-26
The way you set your x vector and then multiply by 60, you have increments of 4*pi (60*(pi/15)). Since you evaulate the cosine of angles that are multiples of 4*pi, those answers are all equal to 1 of course,then you multiply each by two.
What are you actually trying to do? Do you want your frequency to be 60 Hz or 60 radians per sample?
I'll assume 60 radians/sample for the moment.
x = 0:0.001:2*pi;
y = 2*cos(60*x);
plot(x,y)
If you want 60 cycles per second
x = 0:0.001:2;
y = 2*cos(2*pi*60*x);
plot(x,y)
  1 个评论
Big Meech
Big Meech 2013-4-26
Hello,
What I'm essentially trying to do is graph the function 2.0*cos(60x) in MATLAB like this: http://www.wolframalpha.com/input/?i=2*cos%2860x%29+graph+from+0+to+3pi
Would I first have to define the 60 in my x vector? I think I know what I have to do now.
Regards

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 2-D and 3-D Plots 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by