what does it mean by writing [~,idx] in code?
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for p= 4:4:population
dists= total_dist(rand_pair(p-3:p));
[~,idx]=min(dists);
best = routes(idx,:);
what idx, ~ means??
5 个评论
merlin toche
2023-3-13
please I posted the question as you asked so well but no answer. I went through this page because for 2 months my concerns have been ignored, can you explain this to me? thank you
采纳的回答
James Tursa
2013-4-27
编辑:James Tursa
2013-4-27
The ~ represents an output that is discarded. It is essentially equivalent to:
[dummy,idx]=min(dists);
clear dummy
For this example, the code wants to work with the index of the minimum value, not the value itself, so the minimum value that is returned is discarded and only the index is retained.
4 个评论
Dyuman Joshi
2023-3-14
Thank you for the response, Adam.
I now know that while a variable that is suppressed is computed, but it is not returned and not stored in the caller's workspace.
I was stuck on an approach on how to show/understand it via code, but it was quite simple -
[~,~,out]=yo(5)
function [a,b,c]=yo(x)
a=x
b=x.^2
c=-x
end
Adam Danz
2023-3-14
Right, and if you suppress the lines within the function,
[~,~,out]=yo(5)
function [a,b,c]=yo(x)
a=x;
b=x.^2;
c=-x;
end
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the cyclist
2013-4-27
编辑:the cyclist
2013-4-27
When you see
>> [a,b,c] = function(...)
then a,b, and c are the output of a function. If you do not want one of the outputs of a function, then you can replace it with the ~ symbol:
>> [a,~,c] = function(...)
and then b will not be output.
1 个评论
James Tursa
2013-4-27
To clarify, the syntax doesn't actually prevent the function from producing the output ... it just causes MATLAB to ignore the output and automatically clear it instead of assigning it to a workspace variable. So using the syntax makes your code cleaner looking but the function will still use the same resources (time & memory) to run.
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