C CODE Generation - Why does my code not terminate?

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HF
HF 2021-2-11
编辑： Walter Roberson 2021-3-8
Hello,
I generated some C code with the Matlab coder. I wrote a main script to run the functions I generated. I dont get any error messages while running my code. However the code wont terminate. I know this question is possibly very diffcult to ask, but did someone face similar difficulties and what are possible reasons that a generated code wont terminate while I did not had any problems with the orignal code in MATLAB? I generated more then 30 functions. I dont think, its a good idea to attach all of them here.
This is my main script:
void main(void)
{
static double x_data[1024];
double Results[18];
double dv[6];
double maxP_tmp;
int Fs;
double tol;
int x_size[1];
int i;
int j;
/* Initialize function 'EV_Code' input arguments. */
/* Initialize function input argument 'x'. */
for (i = 0; i <1024; i++) {
x_data[i] = 1;
}
x_data[3] = 1.2;
x_data[230] = 1.3;
x_data[443] = 1.7;
x_data[354] = 1.9;
x_data[146] = 1.6;
x_size[0]= 2;
maxP_tmp = 1.1;
dv[0] = 114.5;
dv[1] = 90.81;
dv[2] = 73.72;
dv[3] = 87.76;
dv[4] = 72.78;
dv[5] = 59.65;
Fs = 1000;
tol = 0.04;
EV_Code_X(x_data, x_size, maxP_tmp, Fs, dv, tol, Results);
EV_Code_X_terminate();
// return 0;
}
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HF
HF 2021-2-11
I paused the simulation after 1 000 000 and 2 000 000 instructions. The program was still executing this particular line.
That is the reason why I am quite confused because I had implemented a condition of maximum number of iteration for the while loop.
Rik
Rik 2021-3-8
I have restored the original question body from the Google cache. Don't remove it again.

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回答（1 个）

Geoff Hayes
Geoff Hayes 2021-2-12
编辑：Walter Roberson 2021-3-8
HF - the code that you mention
for (i = 0; i <= coffset; i++) {
Xm0_data[i] = Xm0->data[(aoffset + 30 * i) - 1];
}
occurs before the while loop so the while isn't the problem. In this case, what is coffset initialized to? Is it a valid or reasonable integer? It seems to get initialized via Xm0 but all I see for this variable is that it is defined as
emxArray_real_T *Xm0;
and later initialized as
emxInit_real_T(&Xm0, 2);
but is that sufficient for
i = Xm0->size[0] * Xm0->size[1];
Xm0->size[0] = 30;
Xm0->size[1] = x_size[0] + 29;
emxEnsureCapacity_real_T(Xm0, i);
? Since i is being initialized before the size, I wonder if that is somehow corrupting the object.
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Geoff Hayes
Geoff Hayes 2021-2-12
The passing of i in emxEnsureCapacity_real_T(Xm0, i) may be irrelevant because of
if (emxArray->data != NULL) {
and this should be null because it is initialized to null in the other function at
emxArray->data = (double *)NULL;
So there is no data to copy into the newly allocated array, so this parameter of i is unimportant.
But in this capacity function, look at this code
newNumel = 1;
for (i = 0; i < emxArray->numDimensions; i++) {
newNumel *= emxArray->size[i];
}
if (newNumel > emxArray->allocatedSize) {
i = emxArray->allocatedSize;
if (i < 16) {
i = 16;
}
while (i < newNumel) {
if (i > 1073741823) {
i = MAX_int32_T;
} else {
i *= 2;
}
}
newData = calloc((unsigned int)i, sizeof(double));
Given what we already know, newNumel should be 30*31=930. The emxArray->allocatedSize is 0 so i is initialized to 16. Then in the while loop we multiply i by 2 on each iteration until it is greater than newNumel and so should be initialized to 1024 which you should be able to confirm with Xm0->allocatedSize. So you should have enough memory allocated in your array. Can you confirm that this allocatedSize is 1024?
Geoff Hayes
Geoff Hayes 2021-2-14
Why do you think that the program skipped the call to emxEnsureCapacity_real_T? Check the Xm0->allocatedSize to see what this value is. (I don't have the MATLAB coder so cannot test out your files.)

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