How to calculate moving average for data

9 次查看（过去 30 天）
Ivan Mich
Ivan Mich 2021-2-22
评论： KALYAN ACHARJYA 2021-2-22
How could I calculate moving average for specified data , having specific overllaping (For example I have a set of data, and I would like to compute moving average). How to make it?
Also I do noy understand how to use movmean(A,k)? What should I put in k value in this function?
Could you please help me?
  5 个评论
显示 3更早的评论
Ivan Mich
Ivan Mich 2021-2-22
Nevermind about overlap. Could you please help me about calculating moving average?
Rik
Rik 2021-2-22
What exactly is it you want to do? For each nth element of your vector you can specify which range of values should be averaged. As the documentation for movmean explains, k denotes how wide that window should be.

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

KALYAN ACHARJYA
KALYAN ACHARJYA 2021-2-22
编辑：KALYAN ACHARJYA 2021-2-22
Here One way: Using Loop (As the data is 1 D)
data=1:60 % Random data as per Attached sample
% Lets Decided the Segment size 5 Data Elements
% Move the window by 3 Elements (60% of 5, remaining 2 (40%) Overlap)
move_av=zeros(1,length(data)/3);
idx=1:3:length(data);
for i=1:length(idx)-4
move_av(i)=mean(data(idx(i):idx(i)+4));
end
move_av
Other related function to avoid the loop blockproc, I will respond as a comment once I do. Or you may get the respond from the expert members
https://in.mathworks.com/help/images/ref/blockproc.html
  7 个评论
显示 5更早的评论
KALYAN ACHARJYA
KALYAN ACHARJYA 2021-2-22
If you consider the moving window size is 1, then its simply average of individual data elements divided by 1. And the result will be same as data
>> data=1:10
data =
1 2 3 4 5 6 7 8 9 10
Here
>> movmean(data,1)
ans =
1 2 3 4 5 6 7 8 9 10
More:
movmean(data,k)
Here k represents the window size
Lets consider k is 3
Result
>> movmean(data,3)
ans =
1.5000 2.0000 3.0000 4.0000 5.0000 6.0000 7.0000 8.0000 9.0000 9.5000

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Descriptive Statistics and Visualization 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by