MATLAB code to create a pattern of matrix

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ANDREW B I 2021-2-24

评论： Rik 2021-2-24

Diagonal

for i=1 to 2n+2,
for j=1 to 2n+2,
 aij=0 ; when i=j
end
 

1st row

for  j= 2 to n+2
 aij=1 
for j=n+3 to 2n+2
 aij=0 

2nd row

for j=3 to n+2
a2j=0
for j=n+3 to 2n+2
a2j=1

3rd row

a34=-1, a3,n+3 = -1
for j=5 to n+2; n+4 to 2n+2

4th to n+1 rows

For i=4 to n+1
For j=1 to 2n+2 and i<j 
When j=i+1
aij = -1
else aij=0
end

(n+2)th row

for i = n+2  and i<j
when j=2n+2
aij=-1
else aij= 0

(n+3 to 2n+1) rows

for i=n+3 to 2n+1 and i<j
           when j=i+1
               aij=1
            else aij=0 

lower diagonal elements

for i>j
        aij=-aij

Walter Roberson 2021-2-24

Rik 2021-2-24

It seems you already have an answer to your other question.

If you don't, please follow my advice there.

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