How to set the Attribute possition in a annotation of type rectangle

2 次查看（过去 30 天）
Maider Marin
Maider Marin 2011-5-17
I made a figure, in that I generated a grid of size say N=5 M=8, and I want to highlight the region between (5,2:end-1) in other color. What I did was make the grid in matlab and then generate the M-file for the case rows=N=5 columns=M=8, then in that figure I insert a rectangle with other color in the area I want to highlig and generate the M-file of the rectangle to obtain its position, and add it at the end of the grid code . Now what I want to do is generalize the code for any value of M or N, so for any value of N, M of the grid the region between (N,2:end-1)is highlated in other color. I could generalize the code of the grid by replacing 5 by N and 8 by M. but I am having problems with the position of the rectangle which are the last two lines of the code. I can not figure out how to set the vertical position of the retangle in terms of the size of the grid (N,M) here some code:
function CreateFigureGrid(N,M)
%CREATEFIGURE
% Auto-generated by MATLAB on 19-Nov-2010 16:49:38
% Create figure
%figure1 = figure('PaperSize',[20.98 29.68]);
figure1 = figure();
% Create axes
axes1 = axes('Parent',figure1,'YTick',0:N,'YGrid','on',...
'XTick',0:M,...
'XGrid','on',...
'XTickLabel',[],...
'YTickLabel',[],...
'Position',[0.1368 0.1153 0.775 0.815],...
'PlotBoxAspectRatio',[M N 1],...
'GridLineStyle','-',...
'DataAspectRatio',[1 1 1]);
% Uncomment the following line to preserve the X-limits of the axes
xlim(axes1,[0 M]);
% Uncomment the following line to preserve the Y-limits of the axes
ylim(axes1,[0 N]);
box(axes1,'on');
hold on
text(0.4,0.5,'S','FontName','Courier New');
text(M-.6,.5,'G');
annotation(figure1,'rectangle','FaceColor',[0.8471 0.1608 0],...
'Position',[.1368+.775/M 0.2024 (.775/M)*(M-2) 0.127]);
% Here are some other examples on how the position change with
%other values of N and M
%[0.2351 0.2024 0.5774 0.127] M=8 N=5
% [0.2143 0.2659 0.619 0.1032] M=10 N=5
% [0.1771 0.3948 0.6949 0.05159] M=20 N=5
.1368 is the x-value of the low-left corner of the axis .775 is the width of the box, I try to do the same with the y-values but itdoes not work, I am missing somenthing maybe the aspect ratio is involved in any way but I could not figure it out I will appreciate any help

请先登录，再回答此问题。

采纳的回答

Ivan van der Kroon
Ivan van der Kroon 2011-5-17
Your annotation (the highlighted rectangle) has little to do with your axes in which you specify the grid. You can see it yourself when you try to zoom in: the grid changes accordingly but the rectangle just sits there. If you want something in the figure use rectangle() (see help file).
For instance I would suggest to change it to
rectangle('Position',[1 0 M-2 1],'FaceColor',[0.8471 0.1608 0])
I kept your color but the position starts at (1,0) since your want it 1 position to the right of the left border but touching the bottom and Matlab treats the bottomleft as the origin. Next it should be M-2 long and 1 high. Be wary; if you change your grid, change this rectangle accordingly.

更多回答（1 个）

Maider Marin
Maider Marin 2011-5-17
I also found a way less elegant form to solved I made N by M matrix called maze all with zeros except in the region I want to highlight and then
[mx my] = find(maze);
plot(my-0.5,0.5,'s','MarkerEdgeColor',... [1 .2 .2],'MarkerFaceColor',[1 .2 .2],'MarkerSize',20);
the only problem is that the markersize is fixed.

类别

在 Help Center 和 File Exchange 中查找有关 Interactive Control and Callbacks 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by