How to work on "for loop" to save different column variable values to single vector?

1 次查看(过去 30 天)
My question is=>
i have two variables, Ea and Ed, Ea contains single value and Ed contains 4 values like this,
Ea=10.5
Ed=51.6149 27.1981 13.2580 2.3396
These are wave energy values for 1 second of audio clip. But i have to calculate energy values for 60 seconds. So i have done storing each energy values in different variables like, Ed1, Ed2, Ed3...Ed60. These are Ed values for 60 seconds.
Now the problem i ve got is=>
i want to store all 1st column values of each variable(Ed1,Ed2,Ed3 till Ed60) in one vector(VEd1,VEd2,VEd3 and VEd4), so that i can draw or plot graph to analyze.
Here VEd1 should contain only 1st column values of all Ed values and also VEd2, VEd3 and VEd4.
I have tried "for" loop but could not get how to do tat... If i wont use any loops here, i wont b able to finish this before my dead line as i have to train the module for different audios.
Here is whatever i have tried... but i got errors...
for i=1:60,
VEa=Ea(i);
end
ERROR: Attempted to access Ea(2); index out of bounds because numel(Ea)=1.
then tried=>
for i=1:60,
VEa=Ea.i;
end
ERROR: Attempt to reference field of non-structure array.
Then i satisfied with this=>
for i=1,
VEd1=[Ed1(i) Ed2(i) Ed3(i) Ed4(i) Ed5(i) Ed6(i) Ed7(i) Ed8(i) Ed9(i) Ed10(i) Ed11(i) Ed12(i) Ed13(i) Ed14(i) Ed15(i) Ed16(i) Ed17(i) Ed18(i) Ed19(i) Ed20(i) Ed21(i) Ed22(i) Ed23(i) Ed24(i) Ed25(i) Ed26(i) Ed27(i) Ed28(i) Ed29(i) Ed30(i) Ed31(i) Ed32(i) Ed33(i) Ed34(i) Ed35(i) Ed36(i) Ed37(i) Ed38(i) Ed39(i) Ed40(i) Ed41(i) Ed42(i) Ed43(i) Ed44(i) Ed45(i) Ed46(i) Ed47(i) Ed48(i) Ed49(i) Ed50(i) Ed51(i) Ed52(i) Ed53(i) Ed54(i) Ed55(i) Ed56(i) Ed57(i) Ed58(i) Ed59(i) Ed60(i)];
end
for i=2,
VEd2=[Ed1(i) Ed2(i) Ed3(i) Ed4(i) Ed5(i) Ed6(i) Ed7(i) Ed8(i) Ed9(i) Ed10(i) Ed11(i) Ed12(i) Ed13(i) Ed14(i) Ed15(i) Ed16(i) Ed17(i) Ed18(i) Ed19(i) Ed20(i) Ed21(i) Ed22(i) Ed23(i) Ed24(i) Ed25(i) Ed26(i) Ed27(i) Ed28(i) Ed29(i) Ed30(i) Ed31(i) Ed32(i) Ed33(i) Ed34(i) Ed35(i) Ed36(i) Ed37(i) Ed38(i) Ed39(i) Ed40(i) Ed41(i) Ed42(i) Ed43(i) Ed44(i) Ed45(i) Ed46(i) Ed47(i) Ed48(i) Ed49(i) Ed50(i) Ed51(i) Ed52(i) Ed53(i) Ed54(i) Ed55(i) Ed56(i) Ed57(i) Ed58(i) Ed59(i) Ed60(i)];
end
for i=3,
VEd3=[Ed1(i) Ed2(i) Ed3(i) Ed4(i) Ed5(i) Ed6(i) Ed7(i) Ed8(i) Ed9(i) Ed10(i) Ed11(i) Ed12(i) Ed13(i) Ed14(i) Ed15(i) Ed16(i) Ed17(i) Ed18(i) Ed19(i) Ed20(i) Ed21(i) Ed22(i) Ed23(i) Ed24(i) Ed25(i) Ed26(i) Ed27(i) Ed28(i) Ed29(i) Ed30(i) Ed31(i) Ed32(i) Ed33(i) Ed34(i) Ed35(i) Ed36(i) Ed37(i) Ed38(i) Ed39(i) Ed40(i) Ed41(i) Ed42(i) Ed43(i) Ed44(i) Ed45(i) Ed46(i) Ed47(i) Ed48(i) Ed49(i) Ed50(i) Ed51(i) Ed52(i) Ed53(i) Ed54(i) Ed55(i) Ed56(i) Ed57(i) Ed58(i) Ed59(i) Ed60(i)];
end
for i=4,
VEd4=[Ed1(i) Ed2(i) Ed3(i) Ed4(i) Ed5(i) Ed6(i) Ed7(i) Ed8(i) Ed9(i) Ed10(i) Ed11(i) Ed12(i) Ed13(i) Ed14(i) Ed15(i) Ed16(i) Ed17(i) Ed18(i) Ed19(i) Ed20(i) Ed21(i) Ed22(i) Ed23(i) Ed24(i) Ed25(i) Ed26(i) Ed27(i) Ed28(i) Ed29(i) Ed30(i) Ed31(i) Ed32(i) Ed33(i) Ed34(i) Ed35(i) Ed36(i) Ed37(i) Ed38(i) Ed39(i) Ed40(i) Ed41(i) Ed42(i) Ed43(i) Ed44(i) Ed45(i) Ed46(i) Ed47(i) Ed48(i) Ed49(i) Ed50(i) Ed51(i) Ed52(i) Ed53(i) Ed54(i) Ed55(i) Ed56(i) Ed57(i) Ed58(i) Ed59(i) Ed60(i)];
end
NOW can u plz tel me how to do all this in a single loop?
i want to know how this all variables can be used to store the appropriate values... As in C- language its not happening here. if u know something about this plz help me... Thank you...

采纳的回答

SL B
SL B 2013-5-16
编辑:SL B 2013-5-16
Why loop when you can just put it in a matrix? You are saying that Ed1 = [51.6149 27.1981 13.2580 2.3396] (this would be a row, but I'm assuming you have it in columns since you said you want the first value in each column of EdXX)
so assuming Edxx are column vectors:
Ed = [Ed1, Ed2, Ed3,.......,Ed60];
Then
Ved1 = Ed(1,:);
Ved2 = Ed(2,:);
Ved3 = Ed(3,:);
Ved4 = Ed(4,:);
  1 个评论
prasanna patil
prasanna patil 2013-5-17
Now u will understand what i meant clearly.
x= input('loop starts from-> ', 's');
y= input('loop starts from-> ', 's');
for i=x:y,
Tw = 25;
Ts = 10;
alpha = 0.97;
R = [ 300 3700 ];
M = 20;
C = 13;
L = 22;
hamming = @(N)(0.54-0.46*cos(2*pi*[0:N-1].'/(N-1)));
x= input('input the audio file-> ', 's');
[ speech, fs, nbits ] = wavread(x);
[MFCCs,FBEs,frames]= mfcc(speech,fs,Tw,Ts,alpha,hamming, R, M, C, L );
[C,L] = wavedec(MFCCs,4,'sym4');
[Ea,Ed] = wenergy(C,L);
VEa(i)=Ea(1);
VEd1(i)=Ed(1);
VEd2(i)=Ed(2);
VEd3(i)=Ed(3);
VEd4(i)=Ed(4);
end
the output will b like this...
loop starts from-> 1
loop starts from-> 2
input the audio file-> 1.wav
input the audio file-> 2.wav
now i can store energy values for many audios in different variables with a single program. :)

请先登录,再进行评论。

更多回答(1 个)

David Sanchez
David Sanchez 2013-5-16
for i=1:4
VEd(k) = [Ed1(i) Ed2(i) Ed3(i) Ed4(i) Ed5(i) Ed6(i) Ed7(i) Ed8(i) Ed9(i) Ed10(i) Ed11(i) Ed12(i) Ed13(i) Ed14(i) Ed15(i) Ed16(i) Ed17(i) Ed18(i) Ed19(i) Ed20(i) Ed21(i) Ed22(i) Ed23(i) Ed24(i) Ed25(i) Ed26(i) Ed27(i) Ed28(i) Ed29(i) Ed30(i) Ed31(i) Ed32(i) Ed33(i) Ed34(i) Ed35(i) Ed36(i) Ed37(i) Ed38(i) Ed39(i) Ed40(i) Ed41(i) Ed42(i) Ed43(i) Ed44(i) Ed45(i) Ed46(i) Ed47(i) Ed48(i) Ed49(i) Ed50(i) Ed51(i) Ed52(i) Ed53(i) Ed54(i) Ed55(i) Ed56(i) Ed57(i) Ed58(i) Ed59(i) Ed60(i)];
end
  2 个评论
prasanna patil
prasanna patil 2013-5-16
sir, i am not clear with your answer. How can i store separate 60 values in 4 separate variables?
I tried on your code but i didn't get what i wanted.
As u said that ll process like this...
for i=1:4,
v(i)=i;
end
>> v
v =
1 2 3 4
prasanna patil
prasanna patil 2013-5-16
and tried this also...
for k=1:4,i=1:4,
VEd(k) = [Ed1(i) Ed2(i) Ed3(i) Ed4(i) Ed5(i) Ed6(i) Ed7(i) Ed8(i) Ed9(i) Ed10(i) Ed11(i) Ed12(i) Ed13(i) Ed14(i) Ed15(i) Ed16(i) Ed17(i) Ed18(i) Ed19(i) Ed20(i) Ed21(i) Ed22(i) Ed23(i) Ed24(i) Ed25(i) Ed26(i) Ed27(i) Ed28(i) Ed29(i) Ed30(i) Ed31(i) Ed32(i) Ed33(i) Ed34(i) Ed35(i) Ed36(i) Ed37(i) Ed38(i) Ed39(i) Ed40(i) Ed41(i) Ed42(i) Ed43(i) Ed44(i) Ed45(i) Ed46(i) Ed47(i) Ed48(i) Ed49(i) Ed50(i) Ed51(i) Ed52(i) Ed53(i) Ed54(i) Ed55(i) Ed56(i) Ed57(i) Ed58(i) Ed59(i) Ed60(i)];
end
i =
1 2 3 4
ERROR: In an assignment A(I) = B, the number of elements in B and I must be the same.

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Instrument Control Toolbox 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by