finding distance of distinct value

1 次查看（过去 30 天）
Mohammad Golam Kibria
Hi, suppose I have a matrix as follows:
I =
1 1 5 1 1 1 8
1 1 1 1 1 1 1
1 1 1 1 1 1 1
1 1 1 2 1 1 1
1 1 1 1 1 6 1
1 1 3 1 1 1 1
I(3,4) is 1 . I need to know the distance of this one from the distinct value of this matrix.i.e distances of 2,3,5,6,8. How to do this easily? and also need the matrix position of that value.Thanks in advance.

请先登录，再回答此问题。

采纳的回答

Andrei Bobrov
Andrei Bobrov 2011-5-18
variant
o34 = zeros(size(I));
o34(3,4)=1;
o34d = bwdist(o34);
distato34 = [I(I~=1) o34d(I~=1)]
more variant
o = [3 4];
dC = arrayfun(@(x)(cumsum(ones(size(I)),x)-o(x)).^2,1:2,'un',0);
d = sqrt(dC{1} + dC{2});
l = I~=1;
out = [I(l) d(l)]
more more variant
[Hi Hj] = find(I~=1);
out = [I(I~=1) sqrt(sum(bsxfun(@minus,[Hi Hj],[3 4]).^2,2))]

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Statistics and Machine Learning Toolbox 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by