Generating random numbers within a range determined by elements in another array
4 次查看(过去 30 天)
显示 更早的评论
Hello,
I was wondering if there is an efficient way to generate a random integer within a range depending on an element in another array. Perhaps a small example will explain better:
1 must generate a random number in [3 7];
2 must generate a random number in [1 3];
3 must generate a random number in [44 66]
So for the vector [3 1 2] I would want to get another vector [59 4 2], for example.
I was thinking of using arrayfun to do this but I don't know if there is a more efficient way?
Any help/advice would be greatly appreciated.
Thanks
0 个评论
采纳的回答
Iain
2013-5-21
编辑:Andrei Bobrov
2013-5-22
Array = [3 7; 1 3; 44 66];
Choose your row, "i"
NewRandom = roundingfunctionofchoice(rand(size(i)).*(Array(i,2)-Array(i,1)) + Array(i,1));
If you set i = [3 1 2], you'll get what you want.
更多回答(1 个)
Image Analyst
2013-5-21
Did you look at the help for rand() and notice the first example? Here it is:
Example 1
Generate values from the uniform distribution on the interval [a, b]:
r = a + (b-a).*rand(100,1);
Basically it all comes down to that. Do that 3 times with different a and b depending on what the 3 numbers are. Is this homework?
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Random Number Generation 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!