Error with image analysis

1 次查看(过去 30 天)
Frank
Frank 2011-5-18
Hello!
I've been trying to get this script working, but I don't know how. What it should be able to do is make the image black and white and be able to pick out the centroid of the object in the image.
Image
Code
i = imread('343A #1.tif');
j = size(i);
imtool(i);
for k = 1:j(1)
for l = 1:j(2)
if i(k,l,1) > 160 & i(k,l,2) > 160
d(k,l) = 1;
else
d(k,l) = 0;
end
end
end
imtool(d);
label = bwlabel(d);
imagesc(label);
[label,num] = bwlabel(d,4);
stats = regionprops(label,'basic');
stats(1).Area
stats(1).Centroid
max_area = max([stats.Area]);
biggrain = find([stats.Area]== max_area);
stats(biggrain).Centroid
Error
??? Attempted to access i(2,51,2); index out of bounds because size(i)=[256,64,1].
Error in ==> TestingCentroid3 at 10 if i(k,l,1) > 160 & i(k,l,2) > 160
  1 个评论
Frank
Frank 2011-5-18
I've changed the image format to a tiff file to suit my problem better, however I am still receiving the same error.

请先登录,再进行评论。

回答(2 个)

Sean de Wolski
Sean de Wolski 2011-5-18
i is apparently a 2d image. what is j (size(i))?
d = I > 160; %don't name your variables i,j as they are the sqrt(-1)
  2 个评论
Frank
Frank 2011-5-18
j = size(i); % compute the size of the ball
Sean de Wolski
Sean de Wolski 2011-5-18
I meant what were the values...

请先登录,再进行评论。


Frank
Frank 2011-5-18
Got it.
clc;
close all;
i = imread('343c001.tif');
j = size(i);
imtool(i);
for k = 1:j(1)
for l = 1:j(2)
if i(k,l,1) > 160 & i(k,l) > 160 %I removed the 2
d(k,l) = 1;
else
d(k,l,1) = 0;
end
end
end
imtool(d);
label = bwlabel(d);
imagesc(label);
[label,num] = bwlabel(d,4);
stats = regionprops(label,'basic');
stats(1).Area
stats(1).Centroid
max_area = max([stats.Area]);
biggrain = find([stats.Area]== max_area);
stats(biggrain).Centroid
  2 个评论
Sean de Wolski
Sean de Wolski 2011-5-18
i(k,l,1) is the same location as i(k,l).
hence instead of both for-loops you could do
d = i>160;
Sean de Wolski
Sean de Wolski 2011-5-18
And I'll repeat: Don't name your variables i,j!

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Import, Export, and Conversion 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by