Storing elements to a matrix

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Mohammad Juned
Mohammad Juned 2021-3-13
评论： Mohammad Juned 2021-3-15
Hi everyone. This my code
clc
clear all
m=[ 1 2 3; 4 5 6; 7 8 9];
c=1;
for k=1:3;
for f= 1:3;
m1(k,f)=(m(c+1,k)+m(c+2,f));
end
end
disp(m1);
for k=1:size(m,2)
M(:,:,k)=m(1,k)+m1;
end
disp(M);
the output of this code is
11 12 13
12 13 14
13 14 15
(:,:,1) =
12 13 14
13 14 15
14 15 16
(:,:,2) =
13 14 15
14 15 16
15 16 17
(:,:,3) =
14 15 16
15 16 17
16 17 18
>>
But I want to save all 27 values in a single matrix
how it can be done
  1 个评论
Sergey Kasyanov
Sergey Kasyanov 2021-3-13
Hello, all 27 values are stored in 3-d dimensional matrix. If you want the 2-d matrix you should to describe what are you want in detail.

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采纳的回答

ANKUR KUMAR
ANKUR KUMAR 2021-3-15
3D data can be converted to 2D using reshape. You just need to reshape your matrix based on your requirements.
A1=reshape(M,3,[],1);
Above code yields to 3 X 9 matrix.
A2=reshape(M,[],3,1);
Above code yields to 9 X 3 matrix.
A3=reshape(M,9,[],1);
Above code yields to 9 X 3 matrix.
A4=reshape(M,[],9,1);
Above code yields to 3 X 9 matrix.
A1 and A4 are identical, and A2 and A3 are identical.

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