picking numbers with specific difference in matlab

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Usama Bin Khalid
Usama Bin Khalid 2021-3-15
评论： Usama Bin Khalid 2021-3-15
I have a data set...like say CAD from 212 to 550 say with a differnce of 1 and have corresponing SA values to these CAD values
But I want to pick numbers at a specific distance and in a specific sequence ..like 212,212.3,212.7,213,213.3,213.7.....so that later on i can interpolate the SA values on these CAD values.
How can i do that!! if there was single difference between numbers that would be simple as i did here picking data with a differenc of 0.5:
CAD= data(:,1);
SA= data(:,2);
CADQ=CAD(1):0.5:CAD(end);
vq = interp1 (CAD, SA, CADQ);
here i was able to pick 212,212.5,213,213.5....and was able to interpolate SA on these CAD values.
now how can i do that..picking CAD data in the sequence 212,212.3,212.7,213,213.3,213.7,214,214.3.....
  1 个评论
Rik
Rik 2021-3-15
I don't understand your question well enough to answer it, but it sounds as if ismember will be helpful.

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采纳的回答

Steven Lord
Steven Lord 2021-3-15
Ran in:
One way is to take advantage of implicit expansion.
x = 212:215;
y = [0; 0.3; 0.7];
z = reshape(x+y, 1, [])
z = 1×12
212.0000 212.3000 212.7000 213.0000 213.3000 213.7000 214.0000 214.3000 214.7000 215.0000 215.3000 215.7000
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Rik
Rik 2021-3-15
Ran in:
Create an array where you repeat 0.3 0.5 enough times, set your starting offset as the first value and then use cumsum to calculate the cumulative sum.
x=repmat([0.3 0.5],1,5)
x = 1×10
0.3000 0.5000 0.3000 0.5000 0.3000 0.5000 0.3000 0.5000 0.3000 0.5000
x(1)=213
x = 1×10
213.0000 0.5000 0.3000 0.5000 0.3000 0.5000 0.3000 0.5000 0.3000 0.5000
x=cumsum(x)
x = 1×10
213.0000 213.5000 213.8000 214.3000 214.6000 215.1000 215.4000 215.9000 216.2000 216.7000
Usama Bin Khalid
Usama Bin Khalid 2021-3-15
Yes it worked perfectly...so we can use this code to interpolate any repetitive values....Thanks

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