using FIND in 3D matrix

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xplore29
xplore29 2013-5-29
I am trying to find the 3rd dimension index value for the following case
A(:,:,1)=[1 2 ; 3 4]
A(:,:,2)=[9 8 ; 4 4]
A(:,:,3)=[2 4 ; 7 4]
B=[1 2 ; 3 4]
How can I use find(.) for this purpose

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采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2013-5-29
idx=find(arrayfun(@(x) isequal(A(:,:,x),B),1:size(A,3)))

更多回答（2 个）

Sean de Wolski
Sean de Wolski 2013-5-29
I would do that like this:
A(:,:,1)=[1 2 ; 3 4];
A(:,:,2)=[9 8 ; 4 4];
A(:,:,3)=[2 4 ; 7 4];
A(:,:,4)=A(:,:,1);
B=[1 2 ; 3 4];
idx = find(all(all(bsxfun(@eq,A,B),1),2))
Find where all elements in rows/cols are equal in pages
  2 个评论
xplore29
xplore29 2013-5-29
I didnt understand why would you declare A(:,:,4)=A(:,:,1).
Azzi Abdelmalek
Azzi Abdelmalek 2013-5-29
It's just an example to test the code

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Andrei Bobrov
Andrei Bobrov 2013-5-29
[ii,jj]=ismember(reshape(A,[],size(A,3))',B(:)','rows');
out = jj(ii);

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