Extract Variable from Filename?

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Kate
Kate 2013-5-29
Hi there,
I'm trying to write a reuseable function for a multitude of data points. My current filename when I download my data is:
sitename.yr.synth.daily.mat
Is there a straightforward way to extract the site name so that I can assign it to a column in the matrix? The year is already a column.
I will need to do this on hundreds of sites and years, so I don't want to code each site name by hand. I also need this so that I can match the site name with other classifications and generate unique file names.
Thanks a million!

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采纳的回答

Matt Kindig
Matt Kindig 2013-5-29
You can use strtok() or other methods, but I prefer regexp here:
filename = 'sitename.yr.synth.daily.mat' %example
pieces = regexp(filename, '\.', 'split'); %divide by periods
sitename = pieces{1};

更多回答（1 个）

Azzi Abdelmalek
Azzi Abdelmalek 2013-5-29
编辑：Azzi Abdelmalek 2013-5-29
file='sitename.yr.synth.daily.mat'
idx=strfind(file,'.')
site=file(1:idx(1)-1)
%or
file='sitename.yr.synth.daily.mat'
idx=regexp(file,'\.' ,'split')
site=idx{1}

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