Mean of matrix subarrays without using a loop.

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Santos García Rosado
评论： Santos García Rosado 2021-3-16
Hi Mathworks community.
I'm trying to calculate the mean value of my matrix subarrays without taking the zero values into account. I know how to do it using a loop, but in this case I'd like to avoid it.
The code should take matrix A:
A = [1 0 3 5 0 7; 0 2 6 0 8 0; 3 5 0 0 2 0]
And calculate the mean value of the subarray for each row in steps of 3. So the output should look like:
Out = [2 6; 4 8; 4 2]
I'm trying to improve this code, since I'll be working with much bigger matrixes and I won't be able to do it manually:
Out = mean(nonzeros(A(1,1:3)));
Any help would be much appreciated.
Thanks in advance,
Santos

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采纳的回答

Stephen23
Stephen23 2021-3-16
编辑：Stephen23 2021-3-16
Ran in:
A = [1 0 3 5 0 7; 0 2 6 0 8 0; 3 5 0 0 2 0]
A = 3×6
1 0 3 5 0 7 0 2 6 0 8 0 3 5 0 0 2 0
B = reshape(A.',3,[]);
B(B==0) = NaN;
C = reshape(mean(B,1,'omitnan'),[],size(A,1)).'
C = 3×2
2 6 4 8 4 2
Or
F = @(s)mean(nonzeros(s.data));
C = blockproc(A,[1,3],F) % requires the Image Toolbox.
C = 3×2
2 6 4 8 4 2

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