Getting a increasing by the nxn matrix inside a for loop

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Mark Loui
Mark Loui 2021-3-18
评论： KSSV 2021-3-18
HI there i dont quite understand how to get a matrix that is increasing by nxn matrix
like for example
n=100
for i=1:n
matrixA=[1x1] matrix
iter1
matrixA=[2x2] matrix
iter 2
and so on until the 100x100 matrix, so
end
it would also help if the matrix i get can be used for the diag function?
Help is appreciated thank you in advance

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KSSV
KSSV 2021-3-18
编辑：KSSV 2021-3-18
n=100 ;
matrixA = cell(n,1) ;
for i=1:n
matrixA{i} = rand(n) ;
end
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KSSV
KSSV 2021-3-18
That any is random....
n=100 ;
matrixA = cell(n,1) ;
for i=1:n
matrixA{i} = rand*diag(repmat(i,1,i)) ;
end

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