Inserting a row into the matrix in each iterations

2 次查看（过去 30 天）
Mark Loui
Mark Loui 2021-3-18
评论： Juan Diego Castillo Cruz 2021-3-19
Hi there i like to ask how can i insert a new row/colum into the matrix with each increasing of the iterations
for i=1:n-1
h(i)=x(i+1)-x(i);
iter_h=iter_h+1;
Dia_1= [1 h(i) h(i+1)]
end
My interest is to add one coloum into Dia_1 for each iterations, for example Dia_1=[1 h(1) h(2) h(3) and so on for every new i, the h(i) will pop up here
How can i do so?
  6 个评论
显示 4更早的评论
Adam Danz
Adam Danz 2021-3-18
I believe Rik is suggesting that your loop is doing what the diff function does.
h = diff(x);
Rik
Rik 2021-3-18
That is indeed what I meant: if you want to calculate x(i+1)-x(i) for all positions of x, then you can simply do diff(x) to get the same result.
I have no clue what you are trying to achieve, so I can't give you a real solution. What do you want to do with Dia_1?
If you have trouble with Matlab basics you may consider doing the Onramp tutorial (which is provided for free by Mathworks).

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Juan Diego Castillo Cruz
编辑：Juan Diego Castillo Cruz 2021-3-18
I understand that you want to make the variable grow every iteration. Then:
Dia_1=[]; %Create a array
for i=1:n-1
h(i)=x(i+1)-x(i);
iter_h=iter_h+1;
Dia_1 = [Dia_1 h(i)] %This insert columns
end
  4 个评论
显示 2更早的评论
Rik
Rik 2021-3-19
Did you already do a basic Matlab tutorial? It sounds like that would be a good time investment.
Juan Diego Castillo Cruz
Juan Diego Castillo Cruz 2021-3-19
I assume that h is a matrix then:
h = ones(m,n-1);
Dia_1 = ones(m,n)
for i=1:n-1
h(:,i) = [i 2*i 3*i]; %For example this vector
Dia_1(:,i+1)=h(:,i).*Dia_1(:,i);
end
This was my understanding.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

产品


版本

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by