How to find the sum of values of a function at mid point of every subinterval?

3 次查看(过去 30 天)
I am trying to run this code but don't know how to write code for finding value of function F at mid point of subinterval say, if my interval is [ti, ti+1] for i=0,1,2, n. and need to find sum of functional value at every (ti +ti+1)/2. I need to do it for Rsum2 in this code.
clc; clear all; format long
%%%%%%%%%%%%%%%%%%%%%%%%%%
alpha=0.8;% fractional index
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
TN=1 % time
N=10
T0=0
tau=TN/N
T=[T0:tau:TN]
X0=0
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
X(1)=X0
F =@(X,T)=X+T
for n=0:N-1
Rsum=0;
for j=1:1:n+2
Rsum=Rsum+2*F (j)
end
Rsum2=0;
for j=1:1:n+1
Rsum2=Rsum2+4*F (j+1/2)
end
X(n+2)=X(1) +(tau^alpha)*Rsum + (tau^alpha)*Rsum2
end

采纳的回答

Matt J
Matt J 2021-3-20
编辑:Matt J 2021-3-20
If your function is vectorized, like in the following example, it is quite simple:
fun=@(tm) tm.^2+ sqrt(tm); %A vectorized function
n=8;
t=sort(rand(1,n)) %interval end points t(i)
t = 1×8
0.0157 0.1988 0.2703 0.3719 0.5549 0.6696 0.7340 0.7594
tmid = t(1:end-1)/2 +t(2:end)/2 %interval mid-points
tmid = 1×7
0.1073 0.2345 0.3211 0.4634 0.6122 0.7018 0.7467
result = sum(fun(tmid))
result = 6.3528
  3 个评论
Mubashara Wali
Mubashara Wali 2021-3-22
Matt J Actually its working when F is a function of T only, but having a problem when F is a function of two independent variables as I mentioned in my code that F =@(X,T)=X+T. I would really appreciate if you can help me in this regard.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Calculus 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by