In this context, old -> previous_approx_of_sol and new -> current_approx_of_sol
Function that returns the Error
1 次查看(过去 30 天)
显示 更早的评论
I have to assign variable names to the following items:
- Exact solution is 15.7214
- Current approximation of the solution is 15.7813
- Previous approximation of the solution is 15.9375
Than I have to write a function that returns the Relative True Error using TRE = 100*abs((exact-approx)/exact) and another function that returns the Absolute Relative Error using ARE= 100*abs((new-old)/new). I need to get the code correct before putting it into a function. I can only use:
- abs()
- function
- for-end
- fprintf
- if-elseif-else-end
- input
- plot
- size()
- while-end
- fprintf
The code I have so far is:
exact_sol = 15.7214;
current_approx_of_sol = 15.7813;
previous_approx_of_sol = 15.9375;
TRE = 100*abs((exact_sol-current_approx_of_sol)/exact_sol);
fprintf("The relative true error is %2.2g. \n", TRE)
ARE = 100*abs((new-previous_approx_of_sol)/new);
fprintf("The absolute relative error is %2.2g. \n", ARE)
I'm not sure if what to do about the "new" variable. I'm not sure if this is correct at all.
0 个评论
回答(1 个)
另请参阅
产品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!