convert Hexadecimal to decimal in text file

9 次查看(过去 30 天)
Hi everyone,
I have a text file with thousand of rows and 8 column, below is some examples of the contents:
00baf 00b4d 00bee 00af7 00bae 00bab 000c8 00c03
00bba 00b2c 00bf5 00b0d 00bbd 00bc47 00c1b 00bfc
00bb5 00b1d 00c07 00b30 00bd0 00be77 00c39 00c04
I want to convert these hexadecimal to decimal value for the whole text file, can someone help me with this. Thank you very much.

采纳的回答

Sulaymon Eshkabilov
Use reshape():
reshape(DECd, 4, 6) % Because your converted data is 24 - by -1
Good luck
  2 个评论
Sulaymon Eshkabilov
% if you'd like to make 8 column of data, then
reshape(DECd, 3, 8) % Because your converted data is 24 - by -1
Dung Tran
Dung Tran 2021-3-30
nice, that works really GOOD. Thank you Mr Sulaymon. Have a good Monday!

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更多回答(1 个)

Sulaymon Eshkabilov
Here is the one of the easy solutions:
FN = 'HD.txt'; % File name
% Open the data file to process:
ID = fopen(FN);
% Scan the file:
data = textscan(ID, '%s'); % NB: All read data is put into a cell array
% Convert the imported cell array data into one
data = data{1};
% Convert Hexidecimal data into Decimal data
DECd = hex2dec(data);
fclose(ID);
Good luck
  1 个评论
Dung Tran
Dung Tran 2021-3-29
编辑:Dung Tran 2021-3-29
Thank you very much, it works for Hex to dec, but the result is only in 1 column, do you know how to modify it into 8 column value ? like example below:
13311 13349 11381 18318 13183 13131
13143 13123 54453 12313 23423 13122
so on...
As your example, you put read data into a cell array. How can I put read data into 8 cell column array ?

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