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Store a particular set points in a new cell array.

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Ricky
Ricky 2013-6-11
Hello Everyone,
I had asked a similar question few weeks back but I think that question was not framed properly so please excuse me for asking the same question again
I have a column vector with values
32.5
25.8
25.91
25.92
16.52
16.7
Now I want to create a cell array such that my first cell contains the first value, my second cell array contains value from 25.8 to 25.92 and finally my third cell array contains the values 16.52 and 16.7 .
How can I solve this problem.
  2 个评论
Matt J
Matt J 2013-6-11
编辑：Matt J 2013-6-11
Your rule for grouping data is not clear. In your example, all numbers grouped together have the same integer part, but possibly different decimal parts. Is that the grouping rule you mean? Also, will the data belonging to the same group always neighbour each other in the input vector?
Ricky
Ricky 2013-6-11
Matt in one cell the data group will always be like a neighbour. So suppose I am measuring distance of a test piece from a reference point. So if the distance is 25 mm I use a tolerance window of 24.5 to 25.5 (that is -0.5 and +0.5)

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回答（3 个）

Matt J
Matt J 2013-6-11
[u,~,j]=unique(floor(inputVector),'stable');
z=histc(j,1:max(j));
result = mat2cell(v,z,1)
Azzi Abdelmalek
Azzi Abdelmalek 2013-6-11
A=[32.5;25.8;25.91;25.92;16.52;16.7];
out{1}=A(1);
out{2)=A(2:4);
out{3}=A(5:6);
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Azzi Abdelmalek
Azzi Abdelmalek 2013-6-11
You can not just tell a large difference, what is for you a large difference? 0.5,10,11000?
Ricky
Ricky 2013-6-11
Actually I want to save the when my object is far from the sensor and when it is closer. So I check if the distance is 32.5 mm it is far. When the distances are 25.8,25.91 these small variation can be due to sensor noise or human errors while taking readings. Similarly in the third set I know the object is around 16 mm away from sensor. Then again I see that object is now far as the distance is 33.5 or 33.6 mm from sensor.

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Azzi Abdelmalek
Azzi Abdelmalek 2013-6-11
A=[32.5;25.2;25.91;25.92;16.52;16.7;17;17.45];
B=fix(A+0.5);
C=unique(B,'stable')
out=cell(numel(C),1);
for k=1:numel(C)
idx=find(ismember(B,C(k)))
out{k,1}=A(idx)
end

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