How can I generate the data for an eight '8' draw?

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Hello, I would like to know how to generate the data for the shape of an eight. I've been trying with some hysteresis functions but nothing gets me close really.
Thank you very much

采纳的回答

David Sanchez
David Sanchez 2013-6-13
You can try with this:
t=0:.1:2*pi;
x = -sin(t);
y = sin(t);
plot(t,x,'*',t,y,'+')
  2 个评论
jadaslg
jadaslg 2013-6-13
Thank you very much! It's kind of what I wanted.
Is there any easy way to extract the x and y datapoints for this figure?

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更多回答(2 个)

Paulo Barbosa
Paulo Barbosa 2016-9-15
div = pi/50; % Resolution
sz = 100; % Number of Points in 2 Pi
th = zeros(1,sz);
th(1) = pi; % Starting at (0,0) and going up.
for i = 2:sz
th(i) = th(i-1)-div;
end
circ_x = fat*cos(th);
circ_y = fat*sin(th);
x1 = circ_x(1:26);
y1 = circ_y(1:26);
% -------------------------------------------
th(1) = 0;
for i = 2:sz*fat
th(i) = th(i-1)+div*fat;
end
cos_x = th;
cos_y = fat*cos(th/fat);
x2 = cos_x(1:51);
y2 = cos_y(1:51);
% -------------------------------------------
th(1) = -pi/2;
for i = 2:sz
th(i) = th(i-1)+div;
end
circ_x = fat*cos(th);
circ_y = fat*sin(th);
x3 = circ_x(1:51)+16;
y3 = circ_y(1:51);
% -------------------------------------------
x4 = x2';
x4 = flipud(x4);
x4 = x4';
y4 = y2';
y4 = flipud(y4);
y4 = -y4';
% -------------------------------------------
th(1) = -pi/2;
for i = 2:sz
th(i) = th(i-1)-div;
end
circ_x = fat*cos(th);
circ_y = fat*sin(th);
x5 = circ_x(1:26);
y5 = circ_y(1:26);
% -------------------------------------------
x = [x1 x2 x3 x4 x5];
y = [y1 y2 y3 y4 y5];
% A plot so you can see each section
figure
hold on
plot(x1,y1,'.r');
plot(x2,y2,'.b');
plot(x3,y3,'.k');
plot(x4,y4,'.g');
plot(x5,y5,'.y');

Carmelo Fabrizio Blanco
t = [0:0.001:10];
f = 10;
x = sin(2*pi*t*f);
y = sin(2*pi*t*2*f);
figure();
plot(x,y);

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