Help with if statement in a calculation loop

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Hello,
I have a problem with a code. I want to calculate some numbers but I want to "limit" my results via a loop.
I want values <1 to be =1, values with >10 to be 10 and the others to be calculated from this equation:
x= x*1.3+0.5. I wrote this code but it is not use
x= 5 + randn * 0.5
if x < 1
x == 1
elseif x > 10
x == 10
else x > 3
x == 1.3* x -0.75
end
Where is the problem?
Thanking you in advance
  2 个评论
Nino Wyssen
Nino Wyssen 2021-4-12
I can see several problems here.
First, Matlab likes the lines to be finished with a semicolon, but this isn't necessary if you don't mind your programm outputting all the operations.
Then, you aren't assigning values. You are comparing them. To assign a new value to a variable you only need one equal sign.
Third, you can't use a condition for you else statment, if you only wnt to execute the command below u need to use another elseif.
From your description I suspect the following code does the right thing for you:
x= 5 + randn * 0.5;
if x < 1
x = 1;
elseif x > 10
x = 10;
else
x = 1.3* x -0.75;
end
even though I think it would be better to use a new variable for your result
x= 5 + randn * 0.5;
if x < 1
y = 1;
elseif x > 10
y = 10;
else
y = 1.3* x -0.75;
end
Ivan Mich
Ivan Mich 2021-4-12
I am sorry but running this code stil values up to 10 exist.
It is no use

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采纳的回答

Stephen23
Stephen23 2021-4-12
The simplest and most efficient solution is to use MIN and MAX:
x = 5 + randn(5,7)*1.5;
x = x*1.3 + 0.5
x = 5×7
7.6491 8.4519 8.8820 8.7385 9.8065 8.6945 8.5660 5.7131 13.1416 6.3650 9.1859 6.9860 9.4199 5.4750 8.8947 7.3018 6.4618 7.2714 9.2859 8.7553 5.7112 8.6327 5.6802 3.2153 9.5393 7.2815 7.1600 11.3087 6.1828 6.8579 9.3617 8.8780 4.6976 3.9478 7.3776
x = min(max(x,1),10) % this is all you need.
x = 5×7
7.6491 8.4519 8.8820 8.7385 9.8065 8.6945 8.5660 5.7131 10.0000 6.3650 9.1859 6.9860 9.4199 5.4750 8.8947 7.3018 6.4618 7.2714 9.2859 8.7553 5.7112 8.6327 5.6802 3.2153 9.5393 7.2815 7.1600 10.0000 6.1828 6.8579 9.3617 8.8780 4.6976 3.9478 7.3776

更多回答(1 个)

Rik
Rik 2021-4-12
编辑:Rik 2021-4-12
The problem is that you assume Matlab will process each element of x separately. Matlab will only do that if you use a loop.
An alternative is to use logical indexing to process x as an array.
L=x<1;
x(L)=1;
L=x>10;
x(L)=10;
L=x>3;
x(L)=1.3* x(L) -0.75;
  4 个评论
Ivan Mich
Ivan Mich 2021-4-12
Because values greater than 10 are shown. This is what I mean
Rik
Rik 2021-4-12
In that case you should use the code Stephen suggested.
If you have a piecewise function you can use the code I suggested.

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